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Tems11 [23]
3 years ago
12

Consequences and application of expansion in physics​

Physics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

When solid material expands in response to an increase in temperature (thermal expansion), it can increase in length in a process known as linear expansion. for an example application of expansion and contraction. ... Strain, a material's response to stress, can cause it to deform.

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What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?
svetoff [14.1K]
Base on my research, within 2 hours you have a number of atoms which remain. 
N= N0*2^(-t/6.020 = N= N0*2^-0.33223= 07943 N0

So, the number of atoms that are being disintegrated is N0-N=N0*(1-0.79430)=0.2057 N0

It must be equal to 15 mCi = 15*3.7*10^7= 5.55*10^8 atoms 

N0= 5.55*10*8/0.2057  = 2.698*10^9 atoms

Therefore, 2.698*10^9 atoms is the number of N0
4 0
3 years ago
Hair sticking to a balloon after it<br> has been rubbed on a girl's head is<br> an example of
Lesechka [4]

Answer:

Friction

Explanation:

6 0
3 years ago
Read 2 more answers
What's faster a slow car or a fast feather?​
krok68 [10]

Answer:

A fast feather

Explanation:

The faster any item is, the more momentum it has

5 0
3 years ago
Read 2 more answers
Para el siguiente conjunto de medidas, calcule EL ERROR RELATIVO PORCENTUAL: 1.34 m, 1.35 m, 1.37 m y 1.36 m
ivanzaharov [21]

Answer:

Ver explicacion abajo

Explanation:

En este caso para poder calcular el error relativo porcentual, es necesario calcular primero el error absoluto, que se calcula de la siguiente forma:

Error absoluto = Resultado exacto - aproximación

Sin embargo, no tenemos el resultado exacto de las medidas, pero podriamos conocerlo tomando el promedio de estas medidas y este es el que tomaremos como el verdadero resultado de las medidas:

Promedio de medidas = 1.34 + 1.35 + 1.37 + 1.36 / 4

Promedio de medidas = 1.355 m

Ya que tenemos el promedio, podemos calcular el error absoluto de cada medida y luego el error relativo porcentual:

Ea1 = 1.355 - 1.34 = 0.015

Ea2 = 1.355 - 1.35 = 0.005

Ea3 = 1.37 - 1.355 = 0.015

Ea4 = 1.36 - 1.355 = 0.005

Ya que tenemos los 4 errores absolutos, es posible calcular el porcentual:

%error relativo = (Error absoluto / resultado exacto) * 100

Aplicando la expresión con cada uno de los valores tenemos:

%Er1 = (0.015/1.34) * 100 = 1.12%

%Er2 = (0.005/1.35) * 100 = 0.37%

%Er3 = (0.015/1.37) * 100 = 1.09%

%Er4 = (0.005/1.36) * 100 = 0.37%

Espero que te sirva.

4 0
3 years ago
A crate is acted upon by a net force of 100N. An acceleration of 5.0 m/s^2 results. What is the rate of the crate?
andreev551 [17]
Is there any other information given? I don't think you can solve this without a time
6 0
4 years ago
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