Answer:
0.2 mm
Explanation:
Assuming the Caliper has 1 mm marks on the main scale. Again, we assume that the 20 division coincides with the 16 main scale division, then we can find the least count by saying
For the given Vernier calipers,
Let one main scale division be = 1 mm.
Since there are 20 Vernier scale divisions that happen to be equal to 16 Main Scale Divisions, we can calculate that
1 Vernier Scale Division = 16/20 Main Scale Division
1 Vernier Scale Division = 0.8 mm.
The least count is finally calculated by saying that
Least Count = 1 Main Scale Division - 1 Vernier Scale Division
Least Count = 1 - 0.8
Least Count = 0.2 mm
Therefore, from the assumptions made above, the least count is 0.2 mm
Answer:
3 m/s
Explanation:
Parameters given:
Mass of first bowling pin, m = 1.7 kg
Initial velocity of first bowling pin, u = 3.8 m/s
Final velocity of first bowling pin, v = 0.8 m/s
Mass of second bowling pin, M = 1.7 kg
Initial velocity of second bowling pin, U = 0 m/s
Let the final velocity of the second bowling pin be V
Using the principle of conservation of momentum:
Total initial momentum = Total final momentum
m*u + M*U = m*v + M*V
(1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)
6.46 = 1.36 + 1.7V
1.7V = 5.1
V = 5.1/1.7 = 3 m/s
Answer:
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Explanation:
Answer:
a =45 m/s2
t = 2 seconds
Explanation:
Hi, to answer this question we have to apply the next formula:
v^2 = u^2 +2 a d
Where:
v = final velocity = 90 m/s
u = initial velocity = 0 m/s (shots from rest)
a = acceleration (m/s2)
d = distance = 90m
90^2 = 0^2 + 2a(90)
Solving for a:
8,100= 180 a
8,100/180 = a
a = 45 m/s^2
For time:
v = u + at
90 = 0 + 45t
90/45=t
t =2 seconds
