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3 years ago

Question 4 (9 points)

Physics

1 answer:

Thepotemich [5.8K]3 years ago

3 0

Answer:

62.7KJ

Explanation:

How many joules are required to heat 200 grams of water from 25˚C to 125˚C? 524.8 kJ

Start with Specific Heat because the water is not going through a phase change.

m= 200 g

Cp= 4.18 J/g˚C .......must be given

∆T= 100˚C - 25˚C = 75˚C

q =mCp∆T

q = (200g)(4.18 J/g˚C)(75˚C)

q = 62700 J = 62.7 kJ

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3 years ago

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3 years ago

You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)

Shalnov [3]

Answer:

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