Answer:
Potential difference is the work done in moving a positive test charge from infinity to the point in question.
Voltage is an expression of PD. (Joules / Coulomb)
Say that a capacitor has a PD of 5 Volts. The work in moving a positive test charge from the positive plate to the negative plate is -5 Joules/Coulomb or -5 volt. (At the positive plate the positive test charge (1 Coulomb) already has a PD of + 5 Volts.)
Answer:
D.
Explanation:
To solve the problem it is necessary to apply the concepts of Destructive and constructive interference. The constructive interference in tin film is given by

Where,
t = thickness
Wavelenght
m= is an integer
n= film/refractive index
We use this equaton because phase change is only present for gasoline air interface, but not at the gasoline-water interface. <em>The minimum t only would be when the value of m=0 then</em>



Therefore the correct answer is D. The minimum thickness of the film to see ab right reflection is 100nm
Answer:
option C
Explanation:
The correct answer is option C
Kinetic energy is the energy which is due to the motion of body.
Potential energy is the energy due to virtue of position of the object.
option A is not true because potential energy is due the position of the body
Option B should be the potential energy not kinetic energy.;
Option D is motion of individual molecule leads to kinetic energy not potential energy.
So, the correct answer is option is the covalent bonds of a sugar molecule is potential energy because of the position of bond.
Electical energy is transformed into heat and light energy
Answer:
(a). Z = 54.54 ohm
(b). R = 36 ohm
(c). The circuit will be Capacitive.
Explanation:
Given data
I = 2.75 A
Voltage = 150 V
rad = 48.72°
(a). Impedance of the circuit is given by


Z = 54.54 ohm
(b). We know that resistance of the circuit is given by

Put the values of Z &
in above formula we get

R = 36 ohm
(c). Since the phase angle is negative so the circuit will be Capacitive.