Newton has 3 Laws specifically The Three Laws of Motion
Answer:
(a). The angle of refraction is 19.26°.
(b). That is proved that the rays in air on either side of the glass are parallel to each other
Explanation:
Given that,
Angle of incidence = 30.0°
Index of reflection of glass = 1.52
(a). We need to calculate the angle of refraction for the ray inside the glass
Using snell's law


Put the value into the formula



(b). We know that,
The incident ray and emerging ray is equal then the ray will be parallel.
We need to prove that the rays in air on either side of the glass are parallel to each other
Using formula for emerging ray


Put the value into the formula



So, 
This is proved.
Hence, (a). The angle of refraction is 19.26°.
(b). That is proved that the rays in air on either side of the glass are parallel to each other
Answer: B) 0.00337 m3.
Explanation:
Given data:
Mass of the ball = 10kg
Weight of the ball in air = 98N
Weight of the ball in water = 65N
Solution:
To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.
= 98 - 65 / 9.8
= 33 / 9.8
= 3.37kg
The volume of the ball is 3.37kg
The density of water is 1kg per Liter.
So 3.37 kg of water would have a volume of 3.37 Liters.
Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).
Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:
P = W/t
We calculate as follows:
500 W = 15000 J / t
t = 30 s</span>
Answer:
The heat flows into the gas during this two-step process is 120 cal.
Explanation:
Given that,
Number of moles = 3
Heat capacity at constant volume = 4.9 cal/mol.K
Heat capacity at constant pressure = 6.9 cal/mol.K
Initial temperature = 300 K
Final temperature = 320 K
We need to calculate the heat flow in to gas at constant pressure
Using formula of heat

Put the value into the formula


We need to calculate the heat flow in to gas at constant volume
Using formula of heat

Put the value into the formula


We need to calculate the heat flows into the gas during two steps
Using formula of total heat



Hence, The heat flows into the gas during this two-step process is 120 cal.