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2 years ago

3. Once water makes it's way through the entire water cycle,

Physics

2 answers:

MaRussiya [10]2 years ago

7 0

Answer:

evaporation

Explanation:

without 4he evaporation it can even start the cycsl

fgiga [73]2 years ago

7 0

Answer:

Explanation:

The water cycle is a filtration cycle that repeats over and over to maintain the water amount and to make it pure to drink and use (if that makes sense)

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Find the force on an object which has the mass of 20kg and an acceleration of 10m/s

Elis [28]

Answer:

200 Newtons

Explanation:

20 kg x 10 m/s squared

4 0

2 years ago

What humidity reading would be the driest?

Lunna [17]

The weather report never tells the "humidity" of the air. It tells the
"RELATIVE humidity". That's the percent of the moisture the air
COULD hold at the current temperature that it's actually holding
right now.

If the air is completely dry, then it's holding NONE of the moisture
that it COULD hold, and the relative humidity is zero percent.

7 0

2 years ago

The smallest group of particles in a crystal that retains the shape of the crystal is called the

alexdok [17]

Answer:

Unit Cell

Explanation:

A unit cell is the smallest fundamental particle of a crystal structure that represents the structure of a crystal.

Long-range, three-dimensional repetitiveness of this unit cell forms a crystal. A unit cell is composed of ions or atoms in a particular arrangement forming a well-defined structure.

Crystal have a sharp melting and boiling point and when cut using a tool, they give a sharp edge on the pieces.

3 0

3 years ago

You set a tuning fork into vibration at a frequency of 683 Hz and then drop it off the roof of the Physics building where the ac

mel-nik [20]

Answer:

The distance traveled by the tuning fork is 9.37 m

Explanation:

Given;

source frequency, $f_s$ = 683 Hz

observed frequency, $f_o$ = 657 Hz

The speed at which the tuning fork fell is calculated by applying Doppler effect formula;

$f_o = f_s [\frac{v}{v + v_s} ]$

where;

$v$ is speed of sound in air = 343 m/s

$v_s$ is the speed of the falling tuning fork

$657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s$

The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;

$v_s^2 = v_o^2 + 2gh$

where;

$v_o$ is the initial speed of the tuning fork = 0

g is acceleration due to gravity = 9.80 m/s²

$v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m$

Therefore, the distance traveled by the tuning fork is 9.37 m

5 0

2 years ago

A circular loop of flexible iron wire has an initial circumference of 170 cm , but its circumference is decreasing at a constant

erastova [34]

Answer:

after 9.00 s ; the magnitude of the induced emf = 0.000944 V

The induced current will be in the clockwise direction.

Explanation:

To find the circumference of the circle ; we use the expression:

C = 2πr

differentiating the above expression to determine the rate of change of the circumference; we have:

$\frac{dC}{dt} = 2 \pi \frac{dr}{dt}$

Here ; the rate of change of the circumference is $\frac{dC}{dt}$

Replacing 12.0 cm/s for $\frac{dC}{dt}$ ; we have :

$2 \pi \frac{dr}{dt} = - 12.0 cm/s ------ \ (equation \ 1 )$

However ;the area of the circle is expressed as:

A = πr²

Also; the rate of change of the area is determined as;

$\frac{dA}{dt} = d \frac{\pi r^2}{dt}$

$\frac{dA}{dt} = 2 \pi r \frac{dr}{dt} ------ \ (equation \ 2)$

Here; the rate of change of area is $\frac{dA}{dt}$

Replacing - 12.0 cm/s for $2 \pi r \frac{dr}{dt}$ in equation (2) ; we have:

$\frac{dA}{dt} =(-12.0 \ cm/s) r ------ \ (equation \ 3)$

Now; after 9.00 s ; the value of circumference of the loop is decreased by:

$C_f = ((12.0 \ cm/s )( \frac{1 \ m}{10^2 \ cm}))(9 \ s)$

= 1.08 m

The expression for the circumference of the loop after 9.00 s is:

$C = C_i - C_f$

Given that :

$C_i ( initial \ circumference) = 170 \ cm = 1.7 \ m$

C = ( 1.7 - 1.08) m

C = 0.62 m

Recall that :

C = 2πr

0.62 = 2×3.14 × r

r = $\frac{0.62}{2*3.14}$

r = 0.099 m

Replacing r = 0.099 m into equation (3)

$\frac{dA}{dt} =((-12.0 \ cm/s )( \frac{1 \ m}{10^2 \ cm}))(0.099 \ m)$

$\frac{dA}{dt} =-0.01188 m^2/s$

From Faraday's law, Induced emf (ε) is expressed as:

$\epsilon = - \frac{d \phi }{dt}$

and the magnetic flux is given as:

$\phi = BAcos \theta$

replacing the value of $\phi$ into above equation; we have:

$\epsilon = - \frac{d \ (BAcos \theta) }{dt}$

= $- B cos \theta \frac{d(A)}{dt}$

where θ = 0 ; B = 0.800 T and $\frac{dA}{dt}$ = -0.0118 m²/s

$\epsilon = -(0.800 \ T) (cos 0) (-0.0118 m^2/s)$

$\epsilon = 0.000944 \ V$

Therefore; after 9.00 s ; the magnitude of the induced emf = 0.000944 V

b) The magnitude of id directing into the plane; However ; considering Lenz's law ; it states that the changes produced in the field will be opposed by the induced current. Thus ; it is found that the direction of the current will be in clockwise direction.

6 0

3 years ago

Read 2 more answers