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3 years ago

In which equation does the oxidation of the underlined compound occur?

Chemistry

1 answer:

zhuklara [117]3 years ago

4 0

Answer:

<em>This is an oxidation-reduction (redox) reaction: </em>

<em> 2 CuII + 4 e- → 2 Cu0 (reduction) </em>

<em> C0 - 4 e- → CIV (oxidation) </em>

<em> CuO is an oxidizing agent, C is a reducing agent. </em>

<em> cuO – Copper(II) oxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02 </em>

<em>Other names: Cupric oxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02, Copper monoxide source: wikidata, accessed: 2019-09-02, Copper oxide source: wikidata, accessed: 2019-09-02 </em>

<em>Appearance: Black to brown powder </em>

<em>C </em>

<em>Names: Carbon black source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Acetylene black source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Channel black source: wikidata, accessed: 2019-09-02source: NIOSH NPG, accessed: 2019-09-02 </em>

<em>Appearance: Odourless black pellets or extremely fine powder source: ICSC, accessed: 2019-09-04; Black, odorless solid. source: NIOSH NPG, accessed: 2019-09-02 </em>

<em>Products:Cu </em>

<em>Names: Copper source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04, Copper (dusts and mists, as Cu) source: NIOSH NPG, accessed: 2019-09-02, Cu source: wikidata, accessed: 2019-09-07 </em>

<em>Appearance: Solid in various forms. turns green on exposure to moist air source: ICSC, accessed: 2019-09-04; Reddish, lustrous, malleable, odorless solid. source: NIOSH NPG, accessed: 2019-09-02 </em>

<em>CO2 </em>

<em>Names: Carbon dioxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, {{plainlist| source: wikipedia, accessed: 2019-09-27, CO2 source: wikidata, accessed: 2019-09-02 </em>

<em>Appearance: Colorless gas source: wikipedia, accessed: 2019-09-27; Odourless colourless compressed liquefied gas source: ICSC, accessed: 2019-09-04; Colorless, odorless gas. [Note: Shipped as a liquefied compressed gas. Solid form is utilized as dry ice.] source: NIOSH NPG, accessed: 2019-09-02</em>

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How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?

zhannawk [14.2K]

The heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J. (approx= 3963J).

<h3>What is Sensible heat? </h3><h3 />

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state.

Q= c×m×∆T

<h3>What is Latent heat? </h3><h3 />

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q= m×L

Where,

L is the latent heat

C= specific heat capacity of ice= 2.108 J/gK

M= 10 g

ΔT= T(final)– T(initial) = 0 °C – (-10 °C)= 10 °C= 10 K

Sensitive heat Q(1) = 2.108×10×10

= 210.8J

<h3>Heat needed to melt ice</h3><h3 />

The specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is

Q(2) = 10× 334

= 3340J

C= specific heat capacity of liquid water is 4.187 J/gK

M= 10 g

ΔT= T(final) – T(initial) = 10 °C – 0 °C= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Q(3) = 4.187×10×10

= 418.7 J.

Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

= 3969.5J

Thus, the heat needed to melt 10 gram of ice from temperature-10°C to 10°C is 3969.5. Therefore, option B is correct option.

learn more about heat :

brainly.com/question/16818736

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8 0

2 years ago

What two objects transmit light?

Anestetic [448]

Answer:

Water, and metal.

Explanation:

6 0

3 years ago

Read 2 more answers

Use standard enthalpies of formation to calculate Δ H ∘ rxn for each reaction. MISSED THIS? Read Section 7.9; Watch KCV 7.9, IWE

Eva8 [605]

Answer:

Standard Heat of Reaction 1 = -136.2 kJ/mol

Standard Heat of Reaction 2 = -41.166 kJ/mol

Standard Heat of Reaction 3 = -136.07 kJ/mol

Standard Heat of Reaction 4 = 279.448kJ/mol

Explanation:

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

The required standard heat of formation for each of the reactants and product above, as obtained from literature is listed below.

C₂H₄ (g), 52.5 kJ/mol

H₂ (g), 0 kJ/mol

C₂H₆ (g), -83.7 kJ/mol

CO (g), -110.525 kJ/mol

H₂O (g), -241.818 kJ/mol

H₂ (g), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

NO₂ (g), 33.2 kJ/mol

H₂O (l), -285.8 kJ/mol

HNO₃ (aq), -206.28 kJ/mol

NO (g), 90.29 kJ/mol

Cr₂O₃ (s), -1128.4 kJ/mol

CO (g), -110.525 kJ/mol

Cr (s), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

Note that