Ok so use trigonometry to work out the vertical component of velocity.
sin(25) =opp/hyp
rearrange to:
30*sin(25) which equals 12.67ms^-1
now use SUVAT to get the time of flight from the vertical component,
V=U+at
Where V is velocity, U is the initial velocity, a is acceleration due to gravity or g. and t is the time.
rearranges to t= (V+u)/a
plug in some numbers and do some maths and we get 2.583s
this is the total air time of the golf ball.
now we can use Pythagoras to get the horizontal component of velocity.
30^2-12.67^2= 739.29
sqrt739.29 = 27.19ms^-1
and finally speed = distance/time
so--- 27.19ms^-1*2.583s= 70.24m
The ball makes it to the green, and the air time is 2.58s
(1) The wavelength of the wave is 1.164 m.
(2) The velocity of the wave is 23.7 m/s.
(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
<h3>
Wavelength of the wave</h3>
A general wave equation is given as;
y(x, t) = A sin(Kx - ωt)
<h3>Velocity of the wave</h3>
v = ω/K
From the given wave equation, we have,
y(x, t) = 0.048 sin(5.4x - 128t)
v = ω/K
where;
- ω corresponds to 128
- k corresponds to 5.4
v = 128/5.4
v = 23.7 m/s
<h3>Wavelength of the wave</h3>
λ = 2π/K
λ = (2π)/(5.4)
λ = 1.164 m
<h3>Maximum speed of the wave</h3>
v(max) = Aω
where;
- A is amplitude of the wave
- ω is angular speed of the wave
v(max) = (0.048)(128)
v(max) = 6.14 m/s
Thus, the wavelength of the wave is 1.164 m.
The velocity of the wave is 23.7 m/s.
The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
Learn more about wavelength here: brainly.com/question/10728818
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Answer:
time spent = 0.2276
Explanation:
given data
distance = 135 mi
usual speed = 65 mph
today speed = 73 mph
solution
we get here time that is express as
time = 
...................1
usual time = 
= 2.0769 h
today time = 
= 1.8493 h
so we get here time spent as
time spent = 2.0769 h - 1.8493 h
time spent = 0.2276
Answer:
The initial velocity of the ball is 28.714 m/s
Explanation:
Given;
time of flight of the ball, t = 2.93 s
acceleration due to gravity, g = 9.8 m/s²
initial velocity of the ball, u = ?
The initial velocity of the ball is given by;
v = u + (-g)t
where;
v is the final speed of the ball at the given time, = 0
g is negative because of upward motion
0 = u -gt
u = gt
u = (9.8 x 2.93)
u = 28.714 m/s
Therefore, the initial velocity of the ball is 28.714 m/s
Answer:
Chemical property - characteristic of something that allows it to change to something new.
Explanation:
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