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Neko [114]
3 years ago
11

Define the types of friction and give FOUR examples of each

Physics
1 answer:
Maurinko [17]3 years ago
8 0
Static Friction is the force that keeps an object at rest
example: pushing against a heavy box but it isnt moving due to the weight of the box and gravity pulling it down

Rolling friction is a resistive force that slows down something thats rolling such as a ball or a wheel
example: a rolling soccer being slowed down from grass

Sliding Friction is the friction created from two object sliding against eachother, just like kinetic friction. It is intended to make the object stop
example: A sled sliding down a hill against snow

Fluid Friction is the force that resist motion in fluid or something moving around a fluid.
example: water pushing against a swimmer when swimming through it
You might be interested in
On a frictionless surface how much force is necessary to accelerate a 0.49 kg object to the left at 4.8 m/s2?
Alenkasestr [34]

Answer:

<h2>2.35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

Hope this helps you

8 0
3 years ago
A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When
malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
1 year ago
The weightlifter's internal store of energy decreased when he lifted the bar.
Mumz [18]

Answer:

The energy returns to the weightlifter's muscles, where it is dissipated as heat.

Explanation:

The energy returns to the weightlifter's muscles, where it is dissipated as heat. As long as the weightlifter controls the weight's descent, their muscles are acting as an overdamped shock absorber, as if the weight were sitting on a piston containing very thick fluid, slowly compressing it downward (and slightly heating up the fluid in the process). Since muscles are complicated biological systems and not simple pistons, they require metabolic energy to maintain tension throughout the controlled descent, so the weightlifter feels like they're putting energy into the weight, even though the weight's gravitational potential energy is being converted into heat within the lifter's muscles.

5 0
3 years ago
Why does the area around the equator stay about the same temperature year round?
Verdich [7]
Axial Tilt and Sun Energy

This axial tilt means that during the Earth's journey around the sun the poles receive varying amounts of sunlight. The equator, however, receives relatively consistent sunlight all year. The consistency of energy means the equator's temperature stays relatively constant all year.
3 0
4 years ago
A child in danger of drowning in a river is being carried downstream by a current that flows due south uniformly with a speed of
tia_tia [17]

Let the rescue boat starts at an angle theta with the North

now its velocity towards East is given as

v_x = 24sin\theta

v_y = -24cos\theta + 3

now in some time "t" it will catch the boy

so we will have

t = \frac{0.5}{24sin\theta}

also we have

t = \frac{2}{-24cos\theta + 3}

now we have

\frac{2}{-24cos\theta + 3} = \frac{0.5}{24sin\theta}

4*24sin\theta = - 24cos\theta + 3

96 sin\theta + 24cos\theta = 3

by solving above we got

\theta = 164 degree

3 0
4 years ago
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