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3 years ago

Can someone help with part B asap

Chemistry

1 answer:

slava [35]3 years ago

8 0

Well, simply put,

There is no Hydrogen Chloride being produced from this reaction, but instead it's Ammonium Chloride.

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The green areas on the diagram show the world's rainforests. What can you conclude about the location of rainforests?

Ber [7]

Answer:

Option A

They are located near the equator

Explanation:

From the diagram, we can observe that all the rain forest zones occur near the equator.

This is because on an annual basis, the equator receives the highest concentration of solar radiation in the whole Earth. This implies that the rate of evaporation of water from the water bodies present is high, and consequently, the amount of rainfall is high also. This abundant sunshine and high rainfall leads to the growth of the tropical rain forests at those regions

6 0

3 years ago

35. a

Mashutka [201]

Bruhhhhhhhhhhhhhhhhhhhhhh

4 0

3 years ago

Describe what happens to the molecules in the ice as temperature of the ice increases

german

Answer:

When you heat ice, the individual molecules gain kinetic energy, but until the temperature reaches the melting point, they don't have energy to break the bonds that hold them in a crystal structure. They vibrate more quickly within their confines as you add heat, and the temperature of the ice goes up.

8 0

3 years ago

Read 2 more answers

Just as the depletion of stratospheric ozone today threatens life on Earth today, its accumulation was one of the crucial proces

inessss [21]

Answer:

(a) rate = -(1/3) Δ[O₂]/Δt = +(1/2) Δ[O₃]/Δt

(b) Δ[O₃]/Δt = 1.07x10⁻⁵ mol/Ls

Explanation:

By definition, t<u>he reaction rate for a chemical reaction can be expressed by the decrease in the concentration of reactants or the increase in the concentration of products:</u>

aX → bY (1)

$rate= -\frac{1}{a} \frac{\Delta[X]}{ \Delta t} = +\frac{1}{b} \frac{\Delta[Y]}{ \Delta t}$

<em>where, a and b are the coefficients of de reactant X and product Y, respectively. </em>

(a) Based on the definition above, we can express the rate of reaction (2) as follows:

3O₂(g) → 2O₃(g) (2)

$rate = -\frac{1}{3} \frac{\Delta[O_{2}]}{\Delta t} = +\frac{1}{2} \frac{ \Delta[O_{3}]}{ \Delta t}$ (3)

(b) From the rate of disappearance of O₂ in equation (3), we can find the rate of appearance of O₃:

$rate = +\frac{1}{2} \frac{\Delta[O_{3}]}{ \Delta t} = -\frac{1}{3} \frac{\Delta[O_{2}]}{ \Delta t}$

$+\frac{\Delta[O_{3}]}{ \Delta t} = -\frac{2}{3} \frac{\Delta[-1.61 \cdot 10^{-5}]}{ \Delta t}$

$\frac{\Delta[O_{3}]}{ \Delta t} = 1.07 \cdot 10^{-5} \frac{mol}{Ls}$

So the rate of appearance of O₃ is 1.07x10⁻⁵ mol/Ls.

Have a nice day!

6 0

4 years ago

Which of these elements has the greatest attraction for electrons in a covalent bond?

umka2103 [35]

Answer:

C) Bromine

Explanation: Bromine needs just one electron to fill its outer shell.

6 0

3 years ago