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melamori03 [73]
3 years ago
6

it took 3.5 hours for a train to travel a distance between two cities at a velocity of 120 miles per hour how many miles Live be

tween the two cities ​
Physics
2 answers:
sweet [91]3 years ago
4 0

Answer:

420 miles

Explanation:

here's the solution :-

distance = speed × time

=》distance = 3.5 × 120

=》distance = 420 miles

AveGali [126]3 years ago
3 0

hope this helps........

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A bat locates insects by emitting 25.3 kHz ultrasonic chirps and then listening for echoes from insects flying around it. Humans
mote1985 [20]

Answer:

Speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.

Explanation:

Given:

Frequency of the bat that is source here, f_S = 25.3 kHz = 25.3 * 10^3 Hz

Frequency of the listener (human), f_L = 20 kHz = 20*10^3 Hz

We have to identify how fast the bat have to fly in order for a person to hear these chirps .

Let the velocity of bat that is source is "Vs" and "Vs" = "Vbat".

Doppler effects formulae :

  • When the source is receding (moving away) f_L=(\frac{V+V_L}{V+V_S}) f_S
  • When the source is approaching  f_L=(\frac{V+V_L}{V-V_S}) f_S
  • Speed of sound in V_S =433.895-343the air (medium), V = 343\ ms^-^1

Using the above formula and considering that the bat is moving away so that the human can listen the chirps also V_L=0 as listener is stationary.

⇒ f_L=(\frac{V+V_L}{V+V_S}) f_S   ⇒ f_L=(\frac{V+0}{V+V_S}) f_S

Re-arranging in terms of Vs.

⇒ V+V_S =\frac{V\times f_S}{f_L}

⇒ V_S =\frac{V\times f_S}{f_L}-V

⇒ V_S =\frac{343\times 25.3\times 10^3}{20\times 10^3}-343

⇒ V_S=90.895 m/s

The speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.

7 0
3 years ago
A 5000 kg truck runs into a 0.5 kg mosquito. Which of the following should not be the same for both?
frutty [35]

Answer:

Force and Change in velocity

Explanation:

The contact time is the exact same, as they have hit eachother, rather than something.

The force is how hard they hit eachother, and due to the weight of each object, and the size, the mosquito has much less force.

The change in velocity is also unequal. While the mosquito gets squished, and is now getting thrown in the other direction, the truck is almost completely uneffected, and it's movement stays the same.

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Construct an example of a food chain that involves mosquitos
Afina-wow [57]
Green plant - cow - human - mosquito
5 0
3 years ago
What is one of Kepler's laws of planetary motion?
Murljashka [212]
Answer a is one of keplers 3 laws
7 0
3 years ago
Read 2 more answers
during a lunar mission, it is necessary to increase the speed of a spacecraft by 2.2 m/s when it is moving at 400 m/s relative t
wel

The initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

<h3>What fraction of the initial mass of the spacecraft?</h3>

Increase the speed: Vf-Vi = 2.2 m/s

Speed of aircraft: Vr = 400 m/s

Speed of ejected products: Vrel = 1000 m/s

The answer is:

V_f - V_i = V_{rel} log_{e} (\frac{mi}{mf})\\\\2.2 = 1000 log_{e} (\frac{mi}{mf})\\\\ log_{e} (\frac{mi}{mf} ) = \frac{2.2}{1000} \\\\ log_{e} (\frac{mi}{mf} ) = 0.0022

\frac{mi}{mf} = e^{0,0022} \\\\\frac{mf}{mi} = e^{-0,0022} \\\\\frac{mi-mf}{mi} = 1 - e^{-0,0022} = 0,00219

So, the initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

Learn more about spaceship speed fraction brainly.com/question/28256735

#SPJ4

3 0
1 year ago
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