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TiliK225 [7]
3 years ago
10

if a kid is practicing for a play and there is an auditorium of loud people that are shouting, and he screams, he hears and echo

, when he screams in a quiet auditorium, he doesn't hear an echo, why is that
Physics
1 answer:
Vilka [71]3 years ago
5 0
Because the sound waves are being observed by the people that are there and it is not empty as in an empty place the sound waves will come back to you.
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If a vibrating string is made shorter (i.e., by holding your finger on it), what effect does
Ghella [55]
  <span>Pitch and frequency are more or less the same thing - high pitch = high frequency. 
The freqency of vibration of a string f = 1/length (L) so as length decreases the frequency increases.</span>
4 0
3 years ago
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
An astronaut on the moon drops a feather from rest (v = 0). The acceleration due to gravity is 1.67 m/s​ 2​ . If the feather beg
olga_2 [115]

Given :

Initial velocity , u = 0 m/s .

Acceleration due to gravity on moon , g_m=1.67\ m/s^2 .

Height , h = 2 m .

To Find :

Final position after falling for 1.5 seconds .

Solution :

We know , by equation of motion :

s=ut+\dfrac{at^2}{2}

Here , a = g_m .

So , equation will transform by :

s=ut+\dfrac{g_mt^2}{2}\\\\s=0+\dfrac{1.67\times 1.5^2}{2}\ m\\\\s=1.88\ m

Therefore , the height form moon's surface is 1.88 m .

Hence , this is the required solution .

6 0
3 years ago
Assuming the diode is ideal but with a forward voltage drop of. 65 volts, what is the current in ma if v1=0v, and r1=490ω?
weeeeeb [17]

The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.

To find the answer, we have to know more about the ideal diode.

<h3>What is an ideal diode?</h3>
  • A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
  • A semiconductor diode is the kind of diode that is used the most commonly.
  • It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
<h3>How to find the current in ideal diode?</h3>
  • Here we have given with the values,

                       V_2=65V\\V_1=0V\\R_1=490Ohm.

  • We have the expression for current in mA of the ideal diode with forward biased voltage drop as,

                I=\frac{V_2-V_1}{R_1} =\frac{65}{490} =132.6mA

Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.

Learn more about the ideal diode here:

brainly.com/question/14988926

#SPJ4

7 0
2 years ago
A particular car has a weight of 9500 N. What is the mass of the car? 9500 kg 95000 kg 950 kg 2160 kg
Ivenika [448]

950kg. It is W=mg. therefore, mass= W/g which is W/10

=9500/10

=950

8 0
3 years ago
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