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TiliK225 [7]
3 years ago
10

if a kid is practicing for a play and there is an auditorium of loud people that are shouting, and he screams, he hears and echo

, when he screams in a quiet auditorium, he doesn't hear an echo, why is that
Physics
1 answer:
Vilka [71]3 years ago
5 0
Because the sound waves are being observed by the people that are there and it is not empty as in an empty place the sound waves will come back to you.
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Viefleur [7K]
(3) The frictional force exerted by the floor on the box
4 0
3 years ago
How are animals of the coniferous forest well adapted to long, cold winters?
skelet666 [1.2K]
They have thick body coverings
3 0
3 years ago
Determine the capacitive reactance for a 20 uF capacitor that is across a 20 volt, 60 Hz source
aleksandr82 [10.1K]

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}

X_C=132.6\ \Omega

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.

4 0
3 years ago
A)what are oxidation numbers? b) what useful functions do oxidation numbers serve
9966 [12]
<span>A) indicate the general distribution of electrons among bonded atoms in molecular compounds
B)</span>useful in naming compounds, writing formulas, and balancing chemical equations
<span>may be used to determine the simplest chemical formula </span>
5 0
3 years ago
Spaceship 1 and spaceship 2 have equal masses of 150kg. Spaceship 1 has the speed of 0 m/s and spaceship 2 has a speed of 6 m/s.
Anna11 [10]

Answer:

3 m/s

Explanation:

The computation of speed is shown below:-

We will compute the equation by using the law of conservation of momentum; also, the total momentum prior and following the collision must be conserved. Therefore we can write the equation is the following manner:-

m_1 u_1 + m_2 u_2 = (m_1 +m_2)v

where the symbols represent

150 kg is the mass of spaceship 1  = m1

150 kg is the mass of spaceship 2  = m2

0 m/s is the initial velocity of spaceship 1  = u1

6 m/s is the initial velocity of spaceship 2 = u2

and v is the velocity of the 2 ships so that they can collide and combined together

For v we will get the following equation to reach the speed

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}

=\frac{0+(150)(6)}{150+150}

=3 m/s

5 0
3 years ago
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