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xxMikexx [17]
3 years ago
8

After the load impedance has been transformed through the ideal transformer, its impedance is: + . Enter the real part in the fi

rst blank and the imaginary part in the second blank. If a value is negative, include the negative sign. Provide up to four digits of precision. If the exact value can be provided with fewer digits, merely provide the exact value. These instructions pertain to the following blanks as well. What is the total impedance seen by the source? + . What is the current phasor Ig (expressed in rectangular form)?

Engineering
1 answer:
frozen [14]3 years ago
6 0

Answer:

Ig =7.2 +j9.599

Explanation: Check the attachment

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