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xxMikexx [17]
3 years ago
8

After the load impedance has been transformed through the ideal transformer, its impedance is: + . Enter the real part in the fi

rst blank and the imaginary part in the second blank. If a value is negative, include the negative sign. Provide up to four digits of precision. If the exact value can be provided with fewer digits, merely provide the exact value. These instructions pertain to the following blanks as well. What is the total impedance seen by the source? + . What is the current phasor Ig (expressed in rectangular form)?

Engineering
1 answer:
frozen [14]3 years ago
6 0

Answer:

Ig =7.2 +j9.599

Explanation: Check the attachment

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A loss in value caused by an undesirable or hazardous influence offsite is which type of depreciation?
Lubov Fominskaja [6]

External depreciation may be defined as a loss in value caused by an undesirable or hazardous influence offsite.

<h3>What is depreciation?</h3>

Depreciation may be defined as a situation when the financial value of an acquisition declines over time due to exploitation, fray, and incision, or obsolescence.

External depreciation may also be referred to as "economic obsolescence". It causes a negative influence on the financial value gradually.

Therefore, it is well described above.

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5 0
2 years ago
Carbon dating for archeological materials is based on the fact that a plant, after its death, stops absorbing radioactive C-14 a
Olin [163]

Answer:

 t = 2212 years

Explanation:

In radioactive decay processes it is described by the equation

         N = N₀ e^{-\lambda t}

to calculate the activity

        T_{1/2} = log 2 /λ

        λ = log 2 / T_{1/2}

     

        λ = log 2 /5715

        λ = 5.267 10⁻⁵

now the amount of carbon 14 is N₀ = 0.1%, the sample contains an amount of N = 0.089%

          N / N₀ = e^{-\lambda t}

          -λ t = ln N / N₀

           t = - 1 /λ  ln N /N₀

           t = 1 / 5.267 10⁻⁵   ln (0.089 / 0.1)

           t = 2,212 10³ years

           t = 2212 years

8 0
3 years ago
A material with a yield strength of 40 kpsi and an endurance strength of 20 kpsi is intended for an application with a von Mises
wlad13 [49]

To solve this problem we will apply the concepts related to Soderberg's relation, which will allow us to find the safety factor based on yield stress, endurance strength, the mean and average stress. The mean and average stress values can be found through the alternating Stress previously given. We will proceed by defining the known values, that is

Yield stress \sigma_y = 40ksi

Endurance strength \sigma_e = 20ksi

The two values for alternating stress are

\sigma_1 = 17ksi

\sigma_2 = 3ksi

We know that mean stress is

\sigma_m = \frac{\sigma_1+\sigma_2}{2}

\sigma_m = \frac{17+3}{2} = 10ksi

And the average stress is

\sigma_v = \frac{\sigma_1-\sigma_2}{2}

\sigma_v = \frac{17-3}{2} = 7ksi

According to Soderberg relation

\frac{1}{F.s} = \frac{\sigma_m}{\sigma_y}+\frac{\sigma_v}{\sigma_e}

\frac{1}{F.s} = \frac{10}{40}+\frac{7}{20}

\frac{1}{F.s} = 0.6

F.s = 1.66 \approx 2

Therefore the factor of safety is 2

3 0
3 years ago
Lars is a medical coder. He works for a hospital in Wisconsin but currently lives in Georgia. Lars does his work online and over
Brums [2.3K]
The answer is True because he works in one location while on another
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3 years ago
PLLEEAASSSEEE HELP I KNOW NOTHING ABOUT THIS STUFF
erastovalidia [21]
So 20 plus 60 = 40 then
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3 years ago
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