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lana [24]
3 years ago
5

Donna shines a flashlight and a laser pointer on a sheet of paper. She holds each device at an equal distance from the paper. Ho

w does the light hitting the paper from each device appear different?
The light from the flashlight lights up a larger area of the paper.
The light from the laser pointer lights up a larger area of the paper.
The light from the flashlight magnifies a larger area of the paper.
The light from the laser pointer magnifies a larger area of the paper.
Physics
2 answers:
hjlf3 years ago
6 0

Answer:

A the light on the flash light lights up a bigger area

I'm pretty sure this is right.

Explanation:

netineya [11]3 years ago
3 0

Answer:

a

Explanation:

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The work function for tungsten metal is 4.52eV a. What is the cutoff (threshold) wavelength for tungsten? b. What is the maximum
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Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:

h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.

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in this case  h*ν=W

(h*c)/λ=4.52 eV

λ= (h*c)/4.52 eV

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then we have

(h*c)/(λ)-W= Ek

Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV

Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

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Answer:

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