Answer:
minimum number of photon is 4.05 ×
Explanation:
given data
energy = 50 keV = 50 × eV = 50 ×
× 1.602×
J
thickness = 10^-3
contrast = 1%
to find out
number of incident photons
solution
we know here equation that is
E = n × h × ν .......................1
put here all these value
50 × = n × 6.6×
× c/ 1×
50 × × 1.602×
= n × 6.6×
×( 3 ×
/ 1×
)
solve it and find n
n = 4.05 ×
so here minimum number of photon is 4.05 ×
Answer:
D) Vertically.
Explanation:
A free body diagram is used to represent all the forces acting in a body. forces like, the force of gravity as a result of the gravitational interaction between the object and the Earth (W), the frictional force opposite to the movement of the object (), the normal force due to the plane and the object (N) and the force applied to start the movement in a particular direction (F).
As is show in the free body diagram of the system, W, which is the weight of the body as a consequence of the gravitational force, is at an angle below the inclined plane. that angle between the plane and the x axis is the same that the one of the inclined plane with respect to the horizontal, Since its sides are perpendicular.
Notice how W goes always in the direction to the center of mass of Earth in a vertical path (For comparison see figure (a) and (b)).
