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3 years ago

Suggest one material that is used to make the trampoline surface. Explain your answer.

Physics

1 answer:

DiKsa [7]3 years ago

3 0

Answer:

Polypropylene is the safest material for trampoline mats in the trampoline market. The fibers are heavily woven to make a buoyantly webbed fabric. The fabric is then thermally interlocked to provide a smoother stabilized surface that can withstand constant flexing and stress.

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In a container which can expand or contract (like a balloon, if the temperature of the gas increases, the volume of that gas ___

Usimov [2.4K]

B. Increases
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4 years ago

If you were to be drawn into a black hole, what would happen? To the black hole, not to you.

love history [14]

Answer:

It grows

Explanation:

The blacks holes will absorb

Me hoizontally stretching me like a noodle by the spaghtification process,thus growing bigger.

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3 years ago

A sound wave traveling downward with a speed of about 4000 m per 2nd suddenly slows to 1500 m per 2nd not far below the Earth's

Helga [31]

Answer: the waves probably hits an open cavity

Explanation:

Sound waves transfers energy in form of vibration through water,the speed of sound is greatest in solids followed by liquids and gases,for we to observe such a reduction from 4000m/s to 1500m/s that means it sound had been transmitted through air like open cavity seen in intrusive rock beneath the earth.

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3 years ago

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Which two layers of Earth are mainly composed of iron and nickel? inner core outer core lower mantle upper mantle crust

stich3 [128]

Inner core and outer core

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4 years ago

Read 2 more answers

At time t=0 a positively charged particle of mass m=3.57 g and charge q=9.12 µC is injected into the region of the uniform magne

larisa [96]

Answer:

10.78 s

Explanation:

The force on the charge is computed by using the equation:

$F^{\to}= qE^{\to} +q (v^{\to} + B^{\to}) \\ \\ F^{\to} = (9.12 \times 10^{-6}) *278 (-\hat k) +9.12 *10^{-6} *2.1 *0.18 (\hat i * \hat k) \\ \\ F^{\to} = -2.535 *10^{-3} \hat k -3.447*10^{-6} \hat j$

F = ma

∴

$a ^{\to}= \dfrac{F^{\to}}{m}$

$a ^{\to}= \dfrac{-1}{3.57\times 10^{-3}}(2.535*10^{-3}\hat k + 3.447*10^{-6} \hat j)$

$a ^{\to}=-0.710 \hat k -9.656*10^{-4} \hat j$

At time t(sec; the partiCle velocity becomes $v(t) = 3.78 v_o$

The velocity of the charge after the time t(sec) is expressed by using the formula:

$v^{\to}= v_{o \ \hat i} + a^{\to }t \\ \\ \implies (2.1)\hat i -0.710 t \hat k -9.656 \times 10^{-4} t \hat j = 3.78 v_o \\ \\ \implies (2.1)^2 +(0.710\ t)^2+ (9.656 *10^{-4}t )^2 = (3.78 *2.1^2 \\ \\ \implies 4.41 +0.5041 t^2 +9.324*10^{-7} t^2 = 63.012 \\ \\ \implies 4.41 +0.5041 t^2 = 63.012\\ \\ 0.5041t^2 = 63.012-4.41 \\ \\ t^2 = \dfrac{58.602}{0.5041} \\ \\ t^2 = 116.25 \\ \\ t = \sqrt{116.25} \\ \\ \mathbf{t = 10.78 \ s}$

8 0

3 years ago