Question

Find the size of the resistor which would limit the current to a value of 2 mA when connected to an 8 V supply

Answer 1

Answer:

R = 4000 ohms

Explanation:

Given that,

Current, I = 2 mA

The voltage of the supply, V = 8 V

We need to find the resistance of the resistor. We know that, Ohm's law is as follows :

V = IR

Where

R is resistance

So,

$R=\dfrac{V}{I}\\\\R=\dfrac{8}{2\times 10^{-3}}\\\\\\R=4000\ \Omega$

So, the resistance of the resistor is 4000 ohms.