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GarryVolchara [31]
3 years ago
10

Find the size of the resistor which would limit the current to a value of 2 mA when connected to an 8 V supply

Engineering
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

R = 4000 ohms

Explanation:

Given that,

Current, I = 2 mA

The voltage of the supply, V = 8 V

We need to find the resistance of the resistor. We know that, Ohm's law is as follows :

V = IR

Where

R is resistance

So,

R=\dfrac{V}{I}\\\\R=\dfrac{8}{2\times 10^{-3}}\\\\\\R=4000\ \Omega

So, the resistance of the resistor is 4000 ohms.

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3 years ago
Water is the working fluid in an ideal Rankine cycle. Saturated vapor enters the turbine at 12 MPa, and the condenser pressure i
Brilliant_brown [7]

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3 0
3 years ago
Read 2 more answers
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Answer:

The minimum diameter for each cable should be 0.65 inches.

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