A new 1.2-ha suburban residential development is to be drained by a storm sewer that connects to the municipal drainage system.
The development is considered mostly of single-family dwellings and is characterized by a Manning roughness coefficient for overland flow of 0.20, an average flow length of 200-ft, and an average slope of 0.7%. Local drainage regulations require the sewer pipe to be sized for the peak runoff resulting from a 10-yr rainfall event and a minimum time of concentration of 5-minutes. The following 10-yr IDF curve describes the site rainfall conditions expressing rainfall intensity, ???????? (inch/hour), as a function of storm duration, ???????????????? ( minutes): ????????=315.5????????????????0.81+ 6.19Estimate (a) the time of concentration for this site using kinematic-wave equation, and (b) the peak runoff rate to be handled by the storm sewe
1 answer:
You might be interested in
Answer:
a) Fb= 275.77 lb Fc= 142.75 lb
b) M = -779.97 lb.ft (i.e. 779.97 lb.ft in clockwise direction)
c) Fax = 195 lb
Fay = 337.75 lb
Fbx = 195 lb
Fby = 195 lb
Explanation:
Question: Three tugboats are used to turn a barge in a narrow channel. To avoid producing any net translation of the barge, the forces applied should be couples. The tugboat at point A applies a 390 lb force.
(a) Determine FB and FC so that only couples are applied.
(b) Using your answers to Part (a), determine the resultant couple moment that is produced.
(c) Resolve the forces at A and B into x and y components, and identify the pairs of forces that constitute couples.
Solution:
<u>For this problem Right hand side is positive X direction and Upwards is positive Y direction. Couples and moments will be considered positive in counterclockwise direction.</u>
<u />
a) For no translation condition
∑ & ∑
Hence,
and
Inserting the value of and solving the remaining equations simultaneously yields (magnitudes),
b) Summing up moments
(i.e. 779.97 lb.ft clockwise)
c)
Answer:
Explanation:
Given that
Specific gravity of sea water = 1.025
So density of sea water = 1.025 x 1000
Density of sea water = 1025
We know that
---1
Specific volume
---2
From equation 1 and 2
We can say that
Answer:
acceleration = 24.23 ms⁻¹
Explanation:
Let's gather the data:
The acceleration of the car is given by a = 0.5
The acceleration is the change in the speed in relation to time. In other words:
= a = a = 0.5
...1
Solving the differential equation yields:
v = 0.5 + C₁
Initial conditions : 0 = 0.5 + C₁
C₁ = -5
at any time t, the velocity is: v= 0.5- 5
Solving for distance, s = 0. 5 - 0.5 t - 0.5
18 = 0.5 - 0.5 t - 0.5
t = 3.71 s
Substitute t = 3.71 s
v= 0.5- 5
= 19.85 m/s
a = 0.5 ...1
= 20.3531
an =
=
= 13.1382
Magnitude of acceleration =
=
= 24.23 ms⁻¹ Ans