Explanation:
Given:
v₀ₓ = 15 m/s cos 20° = 14.10 m/s
aₓ = 0 m/s²
v₀ᵧ = 15 m/s sin 20° = 5.13 m/s
aᵧ = -9.8 m/s²
t = 1.5 s
Find: Δx and Δy
Δx = v₀ₓ t + ½ aₓ t²
Δx = (14.10 m/s) (1.5 s) + ½ (0 m/s²) (1.5 s)²
Δx = 21.1 m
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (5.13 m/s) (1.5 s) + ½ (-9.8 m/s²) (1.5 s)²
Δy = -3.33 m
360 degrees. I'm pretty sure
Answer:
1.62 atm
Explanation:
We can solve the problem by using the ideal gas equation:

where:
p = ? is the pressure of the gas in the tire
V = 8.5 L is the volume of the tire
n = 0.55 mol is the number of moles of the gas
R = 0.0821 atm L / K mol is the gas constant
T = 305 K is the temperature of the gas
By re-arranging the equation and substituting the numbers in, we find:
