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3 years ago

An 8.5-l tire is filled with 0.55 mol of gas at a temperature of 305 k. what is the pressure of the gas in the tire?

Physics

1 answer:

const2013 [10]3 years ago

8 0

Answer:

1.62 atm

Explanation:

We can solve the problem by using the ideal gas equation:

$pV=nRT$

where:

p = ? is the pressure of the gas in the tire

V = 8.5 L is the volume of the tire

n = 0.55 mol is the number of moles of the gas

R = 0.0821 atm L / K mol is the gas constant

T = 305 K is the temperature of the gas

By re-arranging the equation and substituting the numbers in, we find:

$p=\frac{nRT}{V}=\frac{(0.55 mol)(0.0821 Latm/Kmol)(305 K)}{8.5 L}=1.62 atm$

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Even in the most advanced circuits, we cannot oscillate electrons back and forth at that rate through wires. But we can oscillat

den301095 [7]

Answer:

the oscillations of the electrons must be in the 10⁸ Hz = 100 MHz range

Explanation:

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2 years ago

A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.

enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

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θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, $KE_{0} = 0.5 mu^{2}$

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, $KE_{f} = 0.5mv^{2}$

a) Using the principle of energy conservation,

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b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

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