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ArbitrLikvidat [17]
4 years ago
15

Which solution is the most concentrated? 2.0 mL of 10 M H2SO4, where H2SO4 has a molar mass of 98 g/mol 5.0 mL of 1.0 M PbSO4, w

here PbSO4 has a molar mass of 303 g/mol 2.0 mL of 10.5 M H2O2, where H2O2 has a molar mass of 34 g/mol 100 mL of 10 M NaCl, where NaCl has a molar mass of 58 g/mol
Chemistry
2 answers:
marishachu [46]4 years ago
7 0

Answer: the option 4) 2.0 mL of 10.5 M H₂O₂, where H₂O₂ has a molar mass of 34 g/mol.

Its concentration is 10.5 M.

Explanation:

1) The unit M means molar. It is the molarity of the solution.

Molartity is the concentration of the solution expressed as number of moles of solute per liters of solution.

The formula of molarity, M, is:

M = number of moles of solute / volume of solution in liters

2) 2.0 mL of 10 M H₂SO₄, where H₂SO₄ has a molar mass of 98 g/mol

⇒ concentration is 10 M

3) 5.0 mL of 1.0 M PbSO₄, where PbSO₄ has a molar mass of 303 g/mol

⇒ concentration = 1.0 M

4) 2.0 mL of 10.5 M H₂O₂, where H₂O₂ has a molar mass of 34 g/mol

⇒ concentration is 10.5 M

5) 100 mL of 10 M NaCl, where NaCl has a molar mass of 58 g/mol

⇒ concentration is 10 M

Mariana [72]4 years ago
3 0

Answer:

its c. 2.0 mL  of 10.5 M H2O2, where H2O2 has a molar mass of 34 g/mol

Explanation:

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A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

8 0
3 years ago
How many molecules of Acetic Acid (CH3COOH) are in a sample that has a mass of 172.90 g?
STatiana [176]

Answer:

17.46× 10²³ molecules

Explanation:

Given data:

Mass of acetic acid = 172.90 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of acetic acid :

Number of moles = mass / molar mass

Number of moles = 172.90 g/ 60.1 g/ol

Number of moles = 2.9 mol

Now the given problem will solve by using Avogadro number.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

2.9 mol × 6.022 × 10²³ molecules  / 1 mol

17.46× 10²³ molecules

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

3 0
3 years ago
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