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Gnoma [55]
3 years ago
6

The three elements of emotion are?

Physics
1 answer:
Alona [7]3 years ago
5 0

Answer: Physical component- state of physiological arousal triggered by autonomic nervous system

Behavioral component- outward expression of emotion, including facial expression and behavior

Cognitive component- appraisal of the situation determine which emotion we are experiencing and why.

Explanation:

hope that helps :)

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A particle moves in a straight line and has acceleration given by a(t) = 12t + 10. Its initial velocity is v(0) = −5 cm/s and it
soldi70 [24.7K]

Answer:

The position function is s_{t}=2t^3+5t^2-5t+9.

Explanation:

Given that,

Acceleration a =12t+10

Initial velocity v_{0} = -5\ cm/s

Initial displacement s_{0}=9\ cm

We know that,

The acceleration is the rate of change of velocity of the particle.

a = \dfrac{dv}{dt}

The velocity is the rate of change of position of the particle

v=\dfrac{dx}{dt}

We need to calculate the the position

The acceleration is

a_{t} = 12t+10

\dfrac{dv}{dt} = 12t+10

a_{t}=dv=(12t+10)dt

On integration both side

\int{dv}=\int{(12t+10)}dt

v_{t}=6t^2+10t+C

At t = 0

v_{0}=0+0+C

C=-5

Now, On integration again both side

v_{t}=\int{ds_{t}}=\int{(6t^2+10t-5)}dt

s_{t}=2t^{3}+5t^2-5t+C

At t = 0

s_{0}=0+0+0+C

C=9

s_{t}=2t^3+5t^2-5t+9

Hence, The position function is s_{t}=2t^3+5t^2-5t+9.

7 0
3 years ago
Which object has no momentum?
zlopas [31]

For one thing, an object that is not moving has no momentum, no matter how much mass it has. Fast objects are also difficult to stop. Bullets have a very small mass, but you wouldn't want to try and stop one! More speed means more momentum - momentum is directly proportional to velocity

5 0
3 years ago
Read 2 more answers
A 10.0 cm3 sample of copper has a mass of 89.6
Romashka-Z-Leto [24]
Density is mass divides by volume, so
89.6g / 10cm^3 =8.96g /cm^3

*cm^3 is a standard unit of volume*
4 0
4 years ago
consider a charge of -15.0 mCmoving to the right a 2.00x10^6 m/s in a mganetic field of .0300 T pointing upwards. What is the ma
77julia77 [94]

Answer:

a = 1.13×10^-8 m/s²

Explanation:

f = ma = qvb \\ a =  \frac{qvb}{m}

q = 15×10^-3 C

v = 2×10^6 m/s

B = 0.03 T

m = 8.00 x10^10 kg

a = 900/8 x10^10

a = 1.13×10^-8 m/s²

5 0
3 years ago
A 0.5 kg block slides down a frictionless semicircular track from a height, h, and collides with a second 1.5 kg block at the bo
Ede4ka [16]

Answer:

h' = 0.062\cdot h

Explanation:

The speed of the 0.5 kg block just before the collision is found by the Principle of Energy Conservation:

U_{g} = K

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot h}

v \approx 4.429\cdot \sqrt{h}

Knowing that collision is inelastic, the speed just after the collision is determined with the help of the Principle of Momentum Conservation:

(0.5\,kg) \cdot (4.429\cdot \sqrt{h}) = (2\,kg)\cdot v

v = 1.107\cdot \sqrt{h}

Lastly, the height reached by the two blocks is:

K = U_{g}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot h'

h' = \frac{v^{2}}{2\cdot g}

h' = \frac{(1.107\cdot \sqrt{h})^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

h' = 0.062\cdot h

3 0
3 years ago
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