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vovikov84 [41]
3 years ago
8

CALCLATE THE EQUATION OF THE LINE THROUGH THE POINTS(-1,1),(4,0),AND(24,-4)

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

7-7 hopes this helps

Step-by-step explanation:

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erastovalidia [21]

Answer:

1. KLP + PLM = 180 degrees (straight line)

2. 3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. x = 27

Step-by-step explanation:

1. Notice that angle KLP + angle PLM is a straight line, so KLP + PLM = 180 degrees (straight line)

2. angle KLP = 3x, so

3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. 5 gives 4x = 108, so x = 27

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3 years ago
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Find the solution to the equation z – 7 = 8.
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oqkrmflwmpoo,d;,apock0-k23[pkpok0okpokp[lpokpo,;'mpm;l,kjpok;,pok0ol;ppppo;l[p[pl[pl[p[pp[pk[pp,o,o,o,l,l,l,,;;;,;,;,plplplpp

Step-by-step explanation:

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3 years ago
A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,
Flura [38]

Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

<u>Step(i</u>):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<em>The level of significance ∝ =0.95</em>

<em>The degrees of freedom = n-1 = 20-1=19</em>

t₀.₉₅ = 1.729

M.E = \frac{1.729 X10 }{\sqrt{20} }

Margin of error = 3.866

Step(ii):-

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<u><em>Given another sample size n =30</em></u>

<em>The level of significance ∝ =0.95</em>

<em>The degrees of freedom = n-1 = 30-1=29</em>

t₀.₉₅ = 1.70

M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24

<u><em>Margin of error = 3.24</em></u>

5 0
4 years ago
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