This problem is asking to predict the pressure in the container at a temperature of 1,135 K with no apparent background; however, in similar problems we can be given a graph having the pressure on the y-axis and the temperature on the x-axis and a trendline such as on the attached file, which leads to a pressure of 21.2 atm by using the given equation and considering the following:
<h3>Graph analysis.</h3>
In chemistry, experiments can be studied, modelled and quantified by using graphs in which we have both a dependent and independent variable; the former on the y-axis and the latter on the x-axis.
In addition, when data is recorded and graphed, one can use different computational tools to obtain a trendline and thus, attempt to find either the dependent or independent value depending on the requirement.
In this case, since the provided trendline by the graph and the program it was put in is y = 0.017x+1.940, we understand y stands for pressure and x for temperature so that we can extrapolate this equation even beyond the plotted points, which is this case.
In such a way, we can plug in the given temperature to obtain the required pressure as shown below:
y = 0.017 ( 1,135 ) + 1.940
y = 21.2
Answer that is in atm according to the units on the y-axis:
Learn more about trendlines: brainly.com/question/13298479
You have to google the answers
Answer:
Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.
Explanation:
Answer:
A. The spectrum shows a single electron in the 2p subshell.
Explanation:
Answer:
9.0 mol
Explanation:
- C₂H₄(g) + 3O₂(g) → 2CO₂ (g) + 2H₂O (g)
In order to <u>convert from moles of CO₂ to moles of O₂</u>, we need to use the <em>stoichiometric coefficients</em> in the balanced reaction. We use a conversion factor that has moles of CO₂ in the denominator and moles of O₂ in the numerator:
- 6.0 mol CO₂ *
= 9.0 mol O₂