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3 years ago

Predict the pressure that would be observed if the container was at a temperature of 1,135 K.

1 answer:

7 0

This problem is asking to predict the pressure in the container at a temperature of 1,135 K with no apparent background; however, in similar problems we can be given a graph having the pressure on the y-axis and the temperature on the x-axis and a trendline such as on the attached file, which leads to a pressure of 21.2 atm by using the given equation and considering the following:

<h3>Graph analysis.</h3>

In chemistry, experiments can be studied, modelled and quantified by using graphs in which we have both a dependent and independent variable; the former on the y-axis and the latter on the x-axis.

In addition, when data is recorded and graphed, one can use different computational tools to obtain a trendline and thus, attempt to find either the dependent or independent value depending on the requirement.

In this case, since the provided trendline by the graph and the program it was put in is y = 0.017x+1.940, we understand y stands for pressure and x for temperature so that we can extrapolate this equation even beyond the plotted points, which is this case.

In such a way, we can plug in the given temperature to obtain the required pressure as shown below:

y = 0.017 ( 1,135 ) + 1.940

y = 21.2

Answer that is in atm according to the units on the y-axis:

Learn more about trendlines: brainly.com/question/13298479

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The following shows the various regulatory methods and their effects on both processes:

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3 years ago

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Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

From the question we have

$P_2 = \frac{2 \times 760}{1.8} = \frac{1520}{1.8} \\ = 844.4444...$

We have the final answer as

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