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slamgirl [31]
3 years ago
10

a car is traveling at 20 meters/seconds anf is brought to rest by applying breaks over a period of 4 seconds. what is its averag

e acceleration over this time in time interval​
Physics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

<em>2.5m/s²</em>

Explanation:

Given the following:

Initial velocity u = 0m/s

Final velocity v = 20m/s

Time t = 4s

Required

average acceleration over this time in time interval​

Using the equation of motion

v = u + at

10 = 0 + a(4)

10 = 4a

a = 10/4

a = 2.5m/s²

<em>Hence its average acceleration over this time in time interval​ is 2.5m/s²</em>

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inn [45]

Answer:

47 m/s

Explanation:

golf club mass, mc = 180 g

golf ball mass, mb = 46 g

initial golf club speed, vc1 = 47 m/s

final golf club speed, vc2 = 35 m/s

initial golf ball speed, vb1 = 0 m/s

final golf ball speed, vb2 = ? m/s

The total momentum is conserved, then:

mc*vc1 + mb*vb1 = mc*vc2 + mb*vb2

Replacing with data and solving (dimension are omitted):

180*47 + 46*0 = 180*35 + 46*vb2

vb2 = (180*47 - 180*35)/46

vb2 = 47 m/s

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3 years ago
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3 years ago
Car a runs a red light and broadsides car b, which is stopped and waiting to make a left turn. car a has a mass of 1,800kg. car
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The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

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since m is the total mass, m = mA + mB, we can write the equation as:

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1800 (vA) = (1800 + 1500) (7.1 m/s)

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The answer is to this question D
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Wouldn't mass stay the same and acceleration increase or am I mistaken?

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