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3 years ago

Which three terms are needed to describe the energy a BASE Jumper has as

Physics

1 answer:

STatiana [176]3 years ago

4 0

A Potential (as she is off the ground she has gravitational potential energy)
B kinetic (because she’s moving down)
and
C gravitational (as gravity is pulling her back down)

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Efficincy of simple machine is 60% what does it mean?<br>

umka2103 [35]

Explanation:

By the statement, Efficiency of a machine is 60% it is meant that 'The work output is 60% of the work input'. If you apply 100J of energy for a machine, it will be able to life load of 60 J only

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3 years ago

Which of the following statements about energy is false?

Artemon [7]

Answer:

Explanation:

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3 years ago

What is the total current in the circuit? (must include unit - A) REWARD = BRAINLEST

Aleksandr-060686 [28]

Answer:6amperes

Explanation:

1/R=1/40 + 1/40

1/R=2/40

Cross multiplying we get

2R=40

Divide both sides by 2

2R/2 =40/2

R=20ohms

Current=voltage ➗ resistance

Current=120 ➗ 20

Current =6amperes

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3 years ago

Read 2 more answers

A rocket's acceleration is 6.0 m/s 2 . Assuming it starts at 0 m/s, how long will it take for the rocket to reach a velocity of

kupik [55]

At=v-u, where u=0

t= v/a=42/6 = 7
Answer: 7 seconds

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3 years ago

Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi

vlada-n [284]

Answer:

The final volume is $0.039 m^3$

Explanation:

Initial temperature: $T1=200C$

Final temperature: $T2=200C$

Initial pressure: $P1=1.50 \times10^6 Pa$

Final pressure: $P2=0.950 \times10^6 Pa$

Initial volume: $V1=0.025m^{3}$

Final volume: $V2=?$

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

$\frac{PV}{T}=nR$ (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

Subscript 2 referring to final state and 1 to initial state.

solving for V2:

$V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=\frac{(1.50 \times10^6)(0.025)(200)}{(200)(0.950 \times10^6)}$

$V_{2}=0.039 m^3$

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4 years ago