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3 years ago

5. Neglect or self-neglect can cause an increase in the symptoms of dementia.

Physics

1 answer:

butalik [34]3 years ago

7 0

Self-neglect can cause an increase in the symptoms of dementia.

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Twoâ cars, 405 kilometersâ apart, begin driving toward each other on aâ long, straight highway. one car travels 70 kilometers pe

mart [117]

The space between the cars closes at (70+65)=135 km/hr. They collide in (405/135)=3 hours after they start moving. In 3 hours, the canary covers (100km/hr x 3)= 300 km.

8 0

4 years ago

The 6 kg block is then released and accelerates to the right, toward the 4 kg block. The surface is rough and the coefficient of

KatRina [158]

Answer:

v =3.41 m/s

Explanation:

given,

mass of block 1 = 6 Kg

mass of another block 2 = 4 Kg

coefficient of friction = 0.3

Assuming 6 Kg block is attached to the spring of spring constant 350 N/m

and distance between the two block is equal to 0.5 m

using formula

$U = \dfrac{1}{2}kx^2$

$U = \dfrac{1}{2}\times 350 \times 0.5^2$

U = 43.75 J

using conservation of energy

KE = U - f.d

where f is the frictional force acting

$\dfrac{1}{2}mv^2 = 43.75- \mu m g d$

$\dfrac{1}{2}\times 6 \times v^2 = 43.75- 0.3\times 6 \times 9.8 \times 0.5$

$v= \sqrt{11.643}$

v =3.41 m/s

4 0

3 years ago

Can someone help me with a science question?

Scrat [10]

What is the question? maybe I can help

8 0

3 years ago

Complete the following sentences.

MrMuchimi

force pull the ball towards it with a force called gravity.
newton

5 0

3 years ago

Your toaster has a power cord with a resistance of 2.2x10^−2 Ω connected in series with a 9.7 Ω nichrome heating element. The po

kati45 [8]

Answer:

(A) 654.545 Kw

(B) $2.885\times 10^5kw$

Explanation:

We have given resistance of the toaster $R_1=2.2\times 10^{-2}ohm=0.022ohm$

Resistance of nichrome heating element $R_2=9.7ohm$

Both the resistances are connected in series so same current will flow through the circuit

Potential difference across the toaster V = 120 volt

So current $i=\frac{120}{0.022}=5454.5454A$

(a) Power dissipated in toaster $P=i^2R=5454.5454^2\times 0.022=654545.441W=654.545kw$

(B) Power dissipated in heating element $P=i^2R=5454.5454^2\times 9.7=2.885\times 10^8W=2.885\times 10^5kw$

5 0

4 years ago