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scZoUnD [109]
3 years ago
14

A person wants to redesign a large room in a house to have less echoing of sound and more sunlight. Which design solution will b

est match the persons needs?
(A.) Hang curtains over the windows that will transmit sound waves and absorb light waves.

(B.) add pillows to the furniture that will reflect sound waves and refract light waves.

(C.) Place a thick white carpet on the floor that will absorb sound waves and reflect light waves.

(D.) Add a large mirror on the wall that will refract sound waves and reflect light waves.
Physics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

(A.) Hang curtains over the windows that will transmit sound waves and absorb light waves

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Which vector correctly indicates the direction of centripetal acceleration experienced by the car?
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Answer:

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3 years ago
The primary_______ cortex specializes in receiving signals from different parts of the body?
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somatosensory

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A disk initially rotated counterclockwise at 1.0 rad/s, but has a counterclockwise angular acceleration of 0.50 rad/s^2 for 2 se
Mumz [18]

Answer:

Initial angular position of the disc is 3 radian

Explanation:

As we know that the angular acceleration of the disc is given as

\alpha = 0.50 rad/s^2

initial angular speed is given as

\omega = 1 rad/s

now we know that angular displacement of the disc is given as

\theta = \omega t + \frac{1}{2}\alpha t^2

\theta = 1(2) + \frac{1}{2}(0.5)(2^2)

\theta = 3 rad

now we have

\theta_f - \theta_i = 3 rad

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8 0
3 years ago
What is the repulsive force between two pith balls that are 9.00 cm apart and have equal charges of -28.0 nC?
Alexus [3.1K]

Answer:

Force, F=8.71\times 10^{-4}\ N

Explanation:

Given that,

Charges on pith balls, q_1=q_2=-28\ nC=-28\times 10^{-9}\ C

Distance between balls, d = 9 cm = 0.09 m

Let F is the repulsive force between two pith balls. We know that the repulsive force between two charges is given by :

F=k\dfrac{q_1^2}{d^2}

F=9\times 10^9\times \dfrac{(-28\times 10^{-9})^2}{(0.09)^2}

F = 0.000871 N

or

F=8.71\times 10^{-4}\ N

So, the repulsive force between the pith balls is 8.71\times 10^{-4}\ N. Hence, this is the required solution.

7 0
4 years ago
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