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ss7ja [257]
3 years ago
9

A load of 102 kg is support Length 2m and cross-setional area 0.1 cm² the wirers stretched by 0.22cm Find The Tensile strain and

stres and young modulus for the wire?
​
Physics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

Given, length of wire, l = 2m

cross sectional area , A = 10^-4 m²

Load , F = 102kgwt = 102 × 9.8 N

extension of wire, ∆l = 0.1cm = 0.001m

Longitudinal stress = F/A

= 102 × 9.8/(10^-4)

= 999.6 × 10^4 ≈ 1 × 10^7 N/m²

Longitudinal strain. = extension of wire/original length of wire = ∆l/l

= 10^-3/2 = 5 × 10^-4

we know, Young's modulus = longitudinal stress/longitudinal strain

= 1 × 10^7/5 × 10^-4

= 20 × 10^9 N/m²

Explanation:

:D

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erma4kov [3.2K]

Answer:

The car C has KE = 100, PE = 0

Explanation:

The principle of conservation of energy states that although energy can be transformed from one form to another, the total energy of the given system remains unchanged.

The energy that a body possesses due to its motion or position is known as mechanical energy. There are two kinds of mechanical energy: kinetic energy, KE and potential energy, PE.

Kinetic energy is the energy that a body possesses due to its motion.

Potential energy is the energy a body possesses due to its position.

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In the diagram above, the cars at various positions of rest or motion are transforming the various forms of mechanical energy, but the total energy is conserved at every point. At the point A, energy is all potential, at B, it is partly potential partly kinetic energy, However, at the point C, all the potential energy has been converted to kinetic energy. At D, some of the kinetic energy has been converted to potential energy as the car climbs up the hill.

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GrogVix [38]

Answer:

70.6 mph

Explanation:

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Distance before locking, d=19.5 ft

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Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

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Initial momentum of car A is given by

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Taking East as positive and west as negative then the sum of initial momentum is

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The common velocity is represented as v_c hence after collision, the final momentum is

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v_a=\frac {156868.8}{1515}=103.5438 ft/s

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