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irakobra [83]
3 years ago
8

What are two types of matter are pure substances

Chemistry
1 answer:
Marta_Voda [28]3 years ago
4 0

Answer:

Elements and compounds are two types of pure substances.

Explanation:

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An acid is any substance that
ehidna [41]

Answer:

C

Explanation: a is incorrect since the lower the ph = more acidic and b is incorrect because it produces hydronium ion and d I’m not sure what it is but I no that base recieve the protons

4 0
2 years ago
Solar energy converts ___ into either ___ energy or electrical energy.
IceJOKER [234]

Answer:

Hey mate....

Explanation:

This is ur answer.....

<h2>Solar radiation can be converted either into thermal energy (heat) or into electrical energy.</h2>

Hope it helps!

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4 0
2 years ago
Read 2 more answers
When trying to determine whether or not an atom gives up electrons easily, do chemists look at electronegativity or ionization p
Archy [21]
Here I found some info at Yahoo answers: https://answers.yahoo.com/question/index?qid=20090119191941AAB7oAb
The more electronegative an atom is the more unwilling it is to lose its electrons in a compound. If you do try to take a very EN atom away from a compound you'll need to apply a lot of energy for that to happen. I can give an example of a single atom though 

<span>Cl has 7 valence electron filled and every atom wants to be like nobles (noble gases), so it's not going to give an electron away b/c it's really close to being like a noble gas. Noble gases are the most stable atoms, which is why I say stability counts.</span>
4 0
3 years ago
In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for
inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)

Reduction at cathode :

Cu^+(aq)+2e^-\rightarrow Cu(s)

Reduction potential of  Cu^{2+} to Cu=E^o_{1}=0.34 V

Oxidation at anode:

Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction potential of  Fe^{2+} to Fe=E^o_{2}=-0.44 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=0.34V -(-0.44 V)=0.78 V

The standard cell potential of the reaction is 0.78 Volts.

3 0
3 years ago
The partial negative charge at one end of a water molecule is attracted to the partial positive
Neporo4naja [7]

Answer:

             Hydrogen Bond

Explanation:

                   Hydrogen bond interactions are formed between the hydrogen atom bonded to most electronegative atoms (i.e. F, O and N) of one molecule and most electronegative atom (i.e. F, O and N) of another molecule.

In this interaction the hydrogen atom has partial positive charge and electronegative atom has partial negative charge.

6 0
2 years ago
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