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jek_recluse [69]
3 years ago
11

How many milliliters of 3.0 M H2SO4 are needed to make 450 mL of 0.10 M H2SO4?

Chemistry
2 answers:
never [62]3 years ago
3 0

Answer:  97.2223 ml

Explanation:

The rule that we will use to solve this problem is:

M2*V1 = M2*V2 where:

M1 is the initial concentration = 3.5 m

V1 is the initial volume = 0.25 l = 250 ml

M2 is the final concentration = 9 m

V2 is the final volume that we need to find

Substitute with the givens in the above equation to get V2 as follows:

3.5*250 = 9*V2

V2 = <em><u>97.2223 ml</u></em>

r-ruslan [8.4K]3 years ago
3 0
97.2223 ) check the comments
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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

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7 0
3 years ago
Read 2 more answers
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