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Art [367]
3 years ago
8

Plssss i need help this is due 12:00 am

Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer: greater

Step-by-step explanan

Vaselesa [24]3 years ago
6 0

Answer:

Greater

Step-by-step explanation:

got it right edge 2020

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A football player weighed 170 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice
alisha [4.7K]

Answer:

he now weighs a total of 182 pounds.

hopefully thats right if not im sorry :c

8 0
4 years ago
Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
Anarel [89]
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
7 0
3 years ago
What does x and y =??????
Kazeer [188]

Answer:

x=30. y=60

Step-by-step explanation:

DG is a straight segment so it sums to 180 degrees. ECG is a right angle so 90 degrees. The rest is described as 2x and x. So 3x=90 degrees. x=30. Eh is also a straight segment. since we know x, we know that ECD is 60 degrees. So y+y=120 degrees. 2y=120. y=60.

6 0
3 years ago
What is the distance between nicholas's school and the post office?
aleksklad [387]
Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

d= \sqrt{(-2-3)^2+(-2-2)^2}  \\  \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16}  \\  \\  \sqrt{41} =\bold{6.4} \ units



Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

d= \sqrt{(1-(-3))^2+(-1-2)^2}  \\  \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9}  \\  \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}
4 0
3 years ago
Name three things that can be easily identified by the equation of a parabola in vertex form
harkovskaia [24]
Golden Gate Bridge, Mountains, Roller Coaster
5 0
3 years ago
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