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prisoha [69]
3 years ago
12

The products obtained from hydroboration-oxidation of cis-2-butene are identical to the products obtained from hydroboration-oxi

dation of trans-2-butene. Draw the products and explain why the configuration of the starting alkene is not relevant in this case.
Chemistry
1 answer:
Rudik [331]3 years ago
7 0

Answer:

a) Attached below

b)  The presence of racemic mixture found as product in both  cases shows that   products are identical ( i.e. they have same configuration

Explanation:

Diagrams of the products obtained from hydroboration-oxidation of cis-2-butene , hydroboration-oxidation of trans-2-butene.

attached below

The presence of racemic mixture found as product in both  cases shows that   products are identical ( i.e. they have same configuration )

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This trend is commonly attributed to the degree of π-bonding in the planar boron trihalide that would be lost upon pyramidalization (the conversion of the trigonal planar geometry to a tetrahedral one) of the BX3 molecule, which follows this trend: BF3 > BCl3 > BBr3 (that is, BBr3 is the most easily pyramidalized). The criteria for evaluating the relative strength of π-bonding are not clear, however. One suggestion is that the F atom is small compared to the larger Cl and Br atoms, and the lone pair electron in the 2pzorbital of F is readily and easily donated, and overlaps with the empty 2pz orbital of boron. As a result, the [latex]\pi[/latex] donation of F is greater than that of Cl or Br. In an alternative explanation, the low Lewis acidity for BF3 is attributed to the relative weakness of the bond in the adducts F3B-L.

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Let's start to understand this question by a simple combustion reaction involving oxidation of Ethane in the presence of Oxygen. When Ethane is burned in the presence of Oxygen it produces Carbon Dioxide and Water respectively. Therefore, the equation is as,

                                C₂H₆  +  O₂    →    CO₂  +  H₂O

Above reaction shows the reaction and the equation is unbalanced. Balancing chemical equation is important because according to law of conservation of mass, mass can neither be created nor destroyed. Hence, we should balance the number of elements on both side.

                                       LHS                      RHS

Carbon Atoms                  2                            1

Hydrogen Atoms              6                           2

Oxygen Atoms                  2                           3

It means this equation is not obeying the law. Now, how to balance? One way is as follow,

                                C₂H₆  +  O₃    →    C₂O₂  +  H₆O

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Carbon Atoms                  2                            2

Hydrogen Atoms              6                           6

Oxygen Atoms                  3                           3

We have balanced the equation by changing the subscripts. But, we have messed up the chemical composition of compounds and molecules like Oxygen is converted into Ozone.

Therefore, we will change the coefficients (moles) to balance the equation as,

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Carbon Atoms                  2                            2

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Now, by changing the coefficients we have balanced the equation without disturbing the chemical composition of compounds and molecules.

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