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Mekhanik [1.2K]
4 years ago
15

A large crystal of potassium magnet is placed in the bottom of a beaker with cold water and left for several hours

Chemistry
1 answer:
icang [17]4 years ago
3 0

Answer:

Diffusion and Dispersion.

Explanation:

The two processes that took place in the given experiment are Diffusion and Dispersion.

When a crystal of potassium magnet is added placed in the bottom of a beaker which contains cold water, after 5 minutes the particles of potassium magnet will diffuse with water through diffusion process and the colour of water turns purple.

After few hours, the colour of solution goes light purple because the tiny particles which were diffused earlier will dispersed in the water and the particles will spread and make the solution lighter in colour.

Hence, the two processes are Diffusion and Dispersion.

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In what way do the oceans and the forests perform a similar function in the carbon cycle, under normal conditions?.
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The ocean absorbs much of the carbon dioxide released when fossil fuels are burned. This extra carbon dioxide lowers the ocean's pH through a process called ocean acidification. Both are important elements for all life on earth. Relationship between the water cycle and the carbon cycle. The sun's energy drives both the carbon cycle and the water cycle.

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8 0
1 year ago
Find the number of Li atoms in 1.50 mole of Li
ale4655 [162]
The molar mass of Li->7g/mol
If 1mol of Li is 7g/mol
1.50mol of Li would be 10.5g/mol
7 0
3 years ago
Write the following in standard notation:<br> 5.1874 x 102
wolverine [178]

Answer:

529,1148

Step-by-step explanation:

5,1874 × 102

= 5,1874 × 102,0

= 529,1148

Conclusion:

Result of 5,1874 × 102 is 529,1148.

3 0
2 years ago
Read 2 more answers
An object becomes positively charged when it
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A. loses electron, bc electrons are negatively charged, protons are positively charged, when electrons are lost, that means there are more protons more
5 0
3 years ago
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If 35.50 cm3 of a NaOH solution are required for the complete neutralization of a 25.00cm3 sample of 0.200mol dm-3 H2SO4, what i
Morgarella [4.7K]
In this question, you are given the NaOH volume but asked for concentration. 
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:

OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
6 0
3 years ago
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