- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
The dilution problem uses the equation :
The initial molarity (concentration) 0.13 M
The initial volume = 0.12 L
The desired molarity (concentration) = 0.23 M
The volume of the desired solution = ( 0.12 + x L )
Substituting values in above equation;
(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)
0.0156 M L = 0.0276 M L + 0.23 x M L
- 0.012 M L = 0.23 x M L
x = - 0.05
Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
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Typically, amides will hydrolyze under <u>milder</u> conditions than esters.
So, second option is correct one.
In acidic medium, amide interact with the water molecules to give a carboxylic aid and salt of ammonia or amine salt whereas in a basic medium, amides interacts with water molecules to give carboxylic aid and salt of ammonia or amine salt. An amides will hydrolyze under milder conditions because amide is least reactive than ester. The electronegativiy of nitrogen is less than oxygen. So, nitrogen transfer more electron cloud than oxygen towards carbonyl carbon. So, carbonyl group of amide hydrolysis in milder condition than ester.
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[H+][OH-] = 1x10-14 = Kw (Memorize this relationship)
(2.70x10-2)[OH-] = 1x10-14
[OH-] = 1x10-14/2.70x10-2
[OH-] = 3.70x10-13 M (assuming you ignore the autoionization of H2O)
Explanation:
The given data is as follows.
Now, according to Michaelis-Menten kinetics,
where, S = substrate concentration = M
Now, putting the given values into the above formula as follows.
=
This means that would approache .