Answer:
Explanation:
Electric field due to long line charge on position of charge at x = 4 m is given as
so we have
now we have
Now electric field due to the charge present at y = 2.0 m
Now total electric field is given as
Answer:
It is the force that opposes motion between two surfaces touching each other. ( OR ) The force between two surfaces that are sliding or trying to slide across each other.
Explanation:
Answer:
field B = µ₀c I / 2πr
The field in the xy plane due to the fact that the two wires are perpendicular to the plane Bx and By are everywhere 0 on the plane.
a) Midway between, the Bz components cancel, so <0, 0, 0> T
b) Bz = µ₀ x I / 2πa + µ₀ x I / 2π(3a) = (µ₀ x I / 2π)(1/a + 1/3a)
Bz = (µ₀ x I / 2πr)(3/3a + 1/3a) = (µ₀x I / 2πr)(4 / 3a) = 2µ₀ x I / 3πa
c) By symmetry, Bz = -2µ₀ x I / 3πa (that is, down into the plane)
To solve this problem we will apply Coulomb's law. For which it tells us that if the charges are constant, the relationship between two forces is equivalent to the inverse of its squared distance. Mathematically this expression can be derived from the Coulomb equation for force:
Here,
k = Coulomb's constant
q = Charge
r = Distance
Under the considerations of the statement we have to
Now replacing,