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vichka [17]
3 years ago
7

For our statistical definition of entropy, we use the equation S = klnW. In this equation, what does k represent?

Physics
1 answer:
Sloan [31]3 years ago
7 0
<span>In the </span>natural logarithm<span> format or in equivalent notation (see: </span>logarithm) as:


base<span> e</span><span> assumed, is called the </span>Planck entropy<span>, </span>Boltzmann entropy<span>, Boltzmann entropy formula, or </span>Boltzmann-Planck entropy formula<span>, a </span>statistical mechanics<span>, </span><span> </span>S<span> is the </span>entropy<span> of an </span>ideal gas system<span>, </span>k<span> is the </span>Boltzmann constant<span> (ideal </span>gas constant R<span> divided by </span>Avogadro's number N<span>), and </span>W<span>, from the German Wahrscheinlichkeit (var-SHINE-leash-kite), meaning probability, often referred to as </span>multiplicity<span> (in English), is the number of “</span>states<span>” (often modeled as quantum states), or "complexions", the </span>particles<span> or </span>entities<span> of the system can be found in according to the various </span>energies<span> with which they may each be assigned; wherein the particles of the system are assumed to have uncorrelated velocities and thus abide by the </span>Boltzmann chaos assumption<span>. 

I hope this helps. </span>
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You are holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. what
pychu [463]

By holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. Therefore, the direction of the force on the charge you are holding will be to the southwest.

Let I hold the charge , q at the centre of given co-ordinate system and two positive charge of equal magnitude Q are placed 1 m to my North and 1 m to my South .

now, both the charge are same nature e.g., positive . Let my charge is also positive (well, you can assume negative too , I am considering positive because it makes me easy to solve) then, both charge repel to my charge.

charge Q placed on east is repelling my charge q toward west . similarly charge Q placed on North is repelling my charge q toward south.

Now , use vector for solve it.

vector F_{net} = vector Fe + vector Fn,

⇒ |F_{net}| = \sqrt{}  F^{2} _{e } + F^{2}_n

⇒ Fe = Fs = KqQ/(1m)² = KqQ

⇒ F_{net} = √{Fe² + Fs²} = √{(kqQ)²+(KqQ)²}

⇒ F_{net}= √2KqQ

Hence, net force act on q {my charge } is √2KqQ and the direction of force is S - W (southwest )direction.

To learn more about positive charges here

brainly.com/question/2903220

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8 0
2 years ago
What is the tangent function used to find and what are its units
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The functions of angles are used to find unknown lengths or angles that can't be measured, in terms of known quantities. The trig functions of angles are ratios of lengths, so they're bare naked numbers without units.
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3 years ago
A rock climber stands on top of a 50 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s a
bagirrra123 [75]
<h2><em>Answer: b) What was the initial speed of the second stone?</em></h2>

Explanation:

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Which property of a substance is not affected by physical changes?
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The answer is A. Reactivity

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A 3000-N force gives an object an acceleration of 15 m/s2. The mass of the object is
7nadin3 [17]
<h3>Answer:</h3>

200 kg

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Newton's Law of Motions </u>

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion

Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)

Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] F = 3000 N

[Given] a = 15 m/s²

[Solve] m = <em>x</em> kg

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Substitute in variables [Newton's Second Law of Motion]:                          3000 N = m(15 m/s²)
  2. [Mass] [Division Property of Equality] Isolate <em>m</em> [Cancel out units]:            200 kg = m
  3. [Mass] Rewrite:                                                                                               m = 200 kg
5 0
2 years ago
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