Since force is a vector quantity, we can find the net force by determining the resultant force. The equation is written below:
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>
Answer:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams
Using Kepler's 3rd law which is: T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds :
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m
Answer:
W = 53.6648 J
Explanation:
W = ∫ F * dr
F = < 4*x i , 3*y j > Newtons
dr = < dx, 0 >
Take the dot product:
F * dr = 4* x * dx
Now replacing numeric
W = ∫ 4 * x * dx , ║ x = ( 0 m ⇒ 5.18 m )
W = ¹ / ₂ * (4 N/m) * x ²
W = (2 N/m) * (5.18 m)²
W = 53.6648 J
Quoting from the article itself:
"Since it is above Earth's atmosphere, it gives us clearer pictures of space than telescopes on Earth can."
