A human nose is capable of detecting how many basic odors?

Note that butane has two possible isomers but that decane has 75 possible isomers. Why does the number of possible isomers go up

iren [92.7K]

Because the number of constitutional, conformational, and geometric isomers goes up with each carbon atom added. There are many more possible configurations and connectivities possible with decane, a 10 carbon chain, than with butane, a 4 carbon chain.

7 0

3 years ago

Determine the molecular formula for the unknown if the molecular mass is 60.0 amu and the empirical formula is ch2o.

mezya [45]

Answer:

The molecular formule for this unknow molecule is C2H4O2

Explanation:

The empirical formula is CH2O ( or better said CnH2nOn)

This means there are 3 elements in the formula of this molecule

⇒ Carbon (C) with a Molar mass of 12 g/mole

⇒ Hydrogen (H) with a Molar mass of 1 g/mole

⇒ Oxygen (O) with a Molar mass of 16 g/mole

We can also notice that the amount of hydrogen should 2x the amount of carbon ( also 2x the amount of oxygen).

The mass of the empirical formule = 12g/ mole + 2* 1 g/mole + 16 g/mole = 30 g/mole

To know what number is n in CnH2nOn we should divide the molecular mass by the empirical mass:

60 g/mole / 30g/mole = 2

this means n = 2

and this will give a molecular formule of C2H4O2

We can control this to calculate the molecular mass:

2*12 + 4* 1 + 2*16 = 24 + 4 + 32 = 60 g/mole

The molecular formule for this unknow molecule is C2H4O2

5 0

4 years ago

A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq

zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4 = 90.03 g/mol

Step 2: Calculate initial moles of H2C2O4

Moles H2C2O4 = mass / molar mass

Moles H2C2O4 = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0

3 years ago

Predict the density of acetylene gas (C2H2) at 0.910 atm and 20oC.

zhuklara [117]

Answer:

d = 0.98 g/L

Explanation:

Given data:

Density of acetylene = ?

Pressure = 0.910 atm

Temperature = 20°C (20+273 = 293 K)

Solution:

Formula:

PM = dRT

R = general gas constant = 0.0821 atm.L/mol.K

M = molecular mass = 26.04 g/mol

0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

23.7 atm.g/mol = d × 24.1 atm.L/mol

d = 23.7 atm.g/mol / 24.1 atm.L/mol

d = 0.98 g/L

6 0

3 years ago

Find the number of moles of water that can be formed if you have 230 mol of hydrogen gas and 110 mol of oxygen gas

Verdich [7]

Answer:

220mol.

Explanation:

Water is H2O. Hydrogen gas is H2. Oxygen gas is O2. You have 220mol of O and 460mol of H. O is the limiting reactant. The ratio O:H2O is 1:1. 220*1=220

3 0

4 years ago