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ser-zykov [4K]
3 years ago
7

A skydiver is falling vertically downward toward the earth with a constant velocity. What can we conclude from this? O His veloc

ity is 9.8 m/s downward. The net force on him is equal to his weight. O His acceleration is not zero but it cannot be determined without more data O His acceleration is 9.8 m/s2 dwnward O The net force on him is zero.
Physics
1 answer:
Alla [95]3 years ago
3 0

Answer:

The net force on him is zero.

Explanation:

The velocity of skydiver is constant.

As we know that the acceleration is rate of change in velocity. So, here velocity os constant it means acceleration of skydiver is zero.

According to Newton's second law

Force acting on a body is equal to the product of mass and velocity of the body.

As acceleration is zero that means the net force acting on the body is zero.

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In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit
ivolga24 [154]

Answer:

m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg    

Explanation:

The football players collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V=1.6m/s.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision, at the initial point the receiver does not have any speed

m_{tackler}*v_{tackler}=(m_{tackler}+m_{receiver})V     (1)

We solve in order to find the receiver mass:

m_{receiver}={m_{tackler}*v_{tackler}/V}-m_{tackler}    

m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg    

5 0
3 years ago
A top-fuel dragster accelerates from rest to a velocity of 100 m/s in 8 s. What is the acceleration?
seropon [69]

Answer:

100 m/s ÷ 8 = 12.5 m/s

Explanation:

You must put multiply (÷)

4 0
3 years ago
During free fusion, the eyes _______ in order to view a stereogram without a stereoscope. A. use the pictorial depth cue B. are
Andru [333]

Answer:

D

Explanation:

During free fusion, the eyes converge or diverge in order to view a stereogram without a stereoscope.

7 0
3 years ago
The 26-kg sphere c is released from rest when θ = 0∘ and the tension in the spring is f = 100 n
aleksandr82 [10.1K]
You are given the mass of a sphere that is 26 kg sphere and it is released from rest when θ = 0°. You are also given the force of the spring that is F = 100 N. You are asked to find the tension of the spring. Imagine that the sphere is connected to a spring. The spring exerts a tension and the spring exerts gravitational pull. This will follow the second law of newton.

T - F = ma
T = ma + F
T = 26kg (9.81m/s²) + 100 N
T = 355.06 N

5 0
4 years ago
A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
denpristay [2]

Answer:

The mass of the rule is 56.41 g  

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

3 0
4 years ago
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