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Gnesinka [82]
3 years ago
7

Brainliest !!!!!!!!!!!!!!!!!!!! Soil erosion is the process by which soil is formed

Chemistry
1 answer:
Shkiper50 [21]3 years ago
6 0
The answer is false.
You might be interested in
difference between an Argon atom with a mass number of 38 (Ar-38) and another Argon atom with a mass number of 45 (Ar-45)?
Kay [80]

The difference between Argon-38 and Argon - 45 is the number of neurons in their nuclei.

<h3>What is Isotope?</h3>

Isotopes are two or more types of atoms of the same element that have the same atomic number but differs in mass numbers due to different numbers of neutrons in their nuclei.

Argon atom with a mass number of 38 (Ar-38) - number of neutrons = 20

Argon atom with a mass number of 45 (Ar-45) - number of neutrons = 27

Thus, the difference between Argon-38 and Argon - 45 is the number of neurons in their nuclei.

Learn more about isotopes here: brainly.com/question/364529
#SPJ1

8 0
2 years ago
A chemist wants to find Kc for the following reaction at 709 K:2NH3(g) + 3 I2 (g) ----&gt; 6HI(g) + N2(g)
irakobra [83]

Answer:

422455.41

Explanation:

Corrected from source,

Given that:-

N2(g) + 3 H2(g)\rightarrow 2NH3(g) \ Kc_1 = 0.314

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant the reaction

2NH3(g)\rightarrow N2(g) + 3 H2(g)

is:

Kc_{1}'=\frac{1}{0.314}

H2(g) + I2(g)\rightarrow 2 HI(g)\  Kc_2 = 51

If the equation is multiplied by a factor of '3', the equilibrium constant of the reverse reaction will be the cube of the equilibrium constant  of initial reaction.

The value of equilibrium constant the reaction

3H2(g) + 3I2(g)\rightarrow 6 HI(g)

is:

Kc_{2}'={51}^3

Adding both the reactions we get the final reaction. So, the equilibrium constants must be multiplied.

The value of equilibrium constant the reaction

2NH3(g) + 3I2(g)\rightarrow 6 HI(g) + N2(g)

is:

Kc'=\frac{1}{0.314}\times {51}^3  = 422455.41

3 0
4 years ago
A birthday balloon had a volume of 14.1 L when the gas inside was at a temperature of 13.9 °C. Assuming no gas escapes, what is
bixtya [17]

Answer:

14.5L

Explanation:

The following data were obtained from the question:

V1 = 14.1L

T1 = 13.9°C = 13.9 + 273 = 286.9K

T2 = 22°C = 22 + 273 = 295K

V2 =?

Using charles' law: V1/T1 = V2 /T2, we can obtain the new volume as follows:

14.1/286.9 = V2 /295

Cross multiply to express in linear form

286.9 x V2 = 14.1 x 295

Divide both side by 286.9

V2 = (14.1 x 295) / 286.9

V2 = 14.5L

Therefore, the new volume = 14.5L

8 0
4 years ago
Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?
monitta

Answer:

200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm (the second choice) would contain an equal number of gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\! (assuming that all four gas samples behave like ideal gases.)

Explanation:

By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.

All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.

The second choice, 200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm, is the only choice where the volume of the sample is also 200\; \rm mL \!. Hence, that choice would be the only one with as many gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\!.

7 0
3 years ago
11 Which compound has the greatest percent composition by mass of sulfur?(1) BaS (3) MgS
harina [27]
Percent composition by mass is calculated (mass of element within compound)/(mass of compound)*100. The lower the total molar mass of the compound, the greater the percent composition of sulfur. In this case, MgS would be that compound, since Mg has the lowest molar mass of the four elements bonded to S.
7 0
4 years ago
Read 2 more answers
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