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larisa86 [58]
3 years ago
12

If Vanadium has an atomic number of 23 and an atomic mass of 50.9425u, how many neutrons are in one atom of Vanadium?

Chemistry
2 answers:
SOVA2 [1]3 years ago
8 0
28 neutrons in Vanadium- round 50.9 to 51 then do 51-23=28
sergejj [24]3 years ago
3 0
<h2>✏28 neutrons are in vanadium.</h2>

<h2 /><h2 /><h2 /><h2 /><h2>❤XxMrprathamxX13❤</h2>
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A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic
yulyashka [42]

Answer: PCl₃O

Explanation:

1) The chemical formula tells the composition of a compound in terms of the ratio of number of atoms of each element that consitutes such compound.

2) You use the chemical symbol for each kind of atom (element) and subscripts to the right of each symbol to tell the number of atoms of each element.

3) For example, O₂ means two atoms of oxygen. Al₂O₃ means two atoms of aluminum and 3 atoms of oxygen.

4) Therefore, PCl₃O means a ratio 1 : 3 : 1 for phosphorus, chlorine, and oxygen.

Hence, PCl₃O is the chemical formula of your compound.

3 0
3 years ago
Read 2 more answers
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4&#10;+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

Thus we can say:  

16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0
3 years ago
How much mass do 2.0 moles of uranium contain
jasenka [17]
The answer is going to be 476.06.
8 0
3 years ago
2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com
Juliette [100K]
Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation. 

molar mass of Na= 23.0 g/mol
 ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L
8 0
2 years ago
A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

We convert this to atm: 1 torr = 0.00132 atm

515.715 Torr = 515.715 * 0.00132 = 0.681 atm

8 0
3 years ago
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