a batsman deflects a ball by an angle of 45 without changing its initial speed which is equal to 54km/h.what is the impulse impa
1 answer:
Answer:
the impulse imparted to the ball is 4.158 kg.m/s
Explanation:
Please find attached image for diagram.
Given;
initial speed of the ball from point A, u = 54km/h = 15 m/s
angle of deflection of the ball along BOP, θ = 45⁰/2 = 22.5⁰
mass of the ball, m = 0.15 kg
the final speed of the ball along B, = u (in reverse direction)
The initial momentum of the ball, P₁ = mucosθ
The final momentum of the ball is P₂ in reverse direction to P₁.
the impulse imparted to the ball = change in momentum of the ball
J = ΔP = P₂ - P₁
J = mucosθ - (-mucosθ)
J = mucosθ + mucosθ
J = 2mucosθ
J = 2(0.15)15cos(22.5⁰)
J = 4.158 kg.m/s
Thus, the impulse imparted to the ball is 4.158 kg.m/s
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Answer:
Explanation:
At the beginning, we have:
V = 4.0 V potential difference across the capacitor
charge stored on the capacitor
Therefore, we can calculate the capacitance of the capacitor:
Later, the battery is replaced with another battery whose voltage is
V = 5.0 V
Since the capacitance of the capacitor does not change, we can calculate the new charge stored:
Since the capacitor has been connected exactly as before, we have that the charge on the positive plate has increased from to
. Therefore, the additional charge that moved to the positive plate is