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Maksim231197 [3]
3 years ago
15

Using the diluted solution from the 100-mL volumetric flask, rinse a 1-mL vol. pipet with a few drops and then pipet exactly 1.0

0-mL into a 50-mL volumetric flask. (Take care not to pipet any solids.) Fill the 50-mL volumetric flask to the mark with acidic FeCl3 solution. Cap and invert to mix the solution. What color is the solution
Chemistry
1 answer:
lara [203]3 years ago
4 0

Answer:

The color of the solution turned a clear brown sort of a copper color

Explanation:

The color of the solution turned a clear brown sort of a copper color.

This is because ASA and the FeCl3 are reacting in a manner that it is resulting in the creation of a metal.

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What is the main difference between ionic<br> compounds and molecular compounds?
Sophie [7]

Answer:

¨molecular compounds are formed by the sharing of electrons, and ionic compounds are formed by the transfer of electrons¨

Explanation:

3 0
3 years ago
Why amino acids are soluble in pH=3 or pH=10 solutions more than it dissolves in pH=7 solutions?
Ray Of Light [21]

Answer:

Solubility is Affected by pH

The pH of an aqueous solution can affect the solubility of the solute. By changing the pH of the solution, you can change the charge state of the solute.

At pH extremes, the amino acid molecules mostly carry a net charge, thus increasing their solubility in polar solvent. At very low or very high pH, the amino acid molecules have increased charge, thus form more salt bonds with water solvent molecules.

An isoelectric point is the pH at which an amino acid exists as its zwitterion. A zwitterion is the dipolar ionic form of an amino acid. ... If the pH is lower (in acidic conditions) than the isoelectric point then the amino acid acts as a base and accepts a proton at the amino group. This gives it a positive change.

An amino acid is usually more soluble in aqueous solvent at pH extremes than it is at a pH near the isolelectric point of the amino acid. (Note that this does not mean that the amino acid is insoluble at a pH near its pI.)

Which of the following statements correctly explains this phenomenon?

(Select all that apply.)

The neutral charge of an amino acid molecule at its isoelectric point will make the molecule hydrophobic.

At pH extremes, the amino acid molecules mostly carry a net charge, thus increasing their solubility in polar solvent.

At very low or very high pH, the amino acid molecules have increased charge, thus form more salt bonds with water solvent molecules.

At pH values far from the isoelectric point, individual amino acid molecules have greater kinetic energy, thus more readily stay in solution.

<h2>Please mark me as brainliest</h2>

8 0
3 years ago
This element is less reactive than lithium and magnesium but more reactive than zinc. Which element is this?
Tamiku [17]
The answer should be:

B. Al (Aluminium)
7 0
3 years ago
Read 2 more answers
What is the mass of a block with a volume of 18 cm^3, and a density of 9.2 g/cm^3?
Semmy [17]

Answer: 165.6grams

Explanation:

Mass of a block = ?

Volume of block = 18 cm^3

Density of block = 9.2 g/cm^3

The density of any object depends on its mass and volume.

i.e Density of block = Mass / volume

9.2 g/cm^3 = Mass / 18 cm^3

Mass = 9.2 g/cm^3 x 18 cm^3

= 165.6 g

Thus, the mass of the block is 165.6grams

6 0
3 years ago
After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid
nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0
3 years ago
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