<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61
<u>Explanation:</u>
We are given:
Initial moles of iodine gas = 0.100 moles
Initial moles of hydrogen gas = 0.100 moles
Volume of container = 1.00 L
Molarity of the solution is calculated by the equation:
![\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20solution%7D%3D%5Cfrac%7B%5Ctext%7BNumber%20of%20moles%7D%7D%7B%5Ctext%7BVolume%7D%7D)
![\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20iodine%20gas%7D%3D%5Cfrac%7B0.1mol%7D%7B1L%7D%3D0.1M)
![\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20hydrogen%20gas%7D%3D%5Cfrac%7B0.1mol%7D%7B1L%7D%3D0.1M)
Equilibrium concentration of iodine gas = 0.0210 M
The chemical equation for the reaction of iodine gas and hydrogen gas follows:
![H_2+I_2\rightleftharpoons 2HI](https://tex.z-dn.net/?f=H_2%2BI_2%5Crightleftharpoons%202HI)
<u>Initial:</u> 0.1 0.1
<u>At eqllm:</u> 0.1-x 0.1-x 2x
Evaluating the value of 'x'
![\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M](https://tex.z-dn.net/?f=%5CRightarrow%20%280.1-x%29%3D0.0210%5C%5C%5C%5C%5CRightarrow%20x%3D0.079M)
The expression of
for above equation follows:
![K_c=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
![[HI]_{eq}=2x=(2\times 0.079)=0.158M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D2x%3D%282%5Ctimes%200.079%29%3D0.158M)
![[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D%280.1-x%29%3D%280.1-0.079%29%3D0.0210M)
![[I_2]_{eq}=0.0210M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.0210M)
Putting values in above expression, we get:
![K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%280.158%29%5E2%7D%7B0.0210%5Ctimes%200.0210%7D%5C%5C%5C%5CK_c%3D56.61)
Hence, the value of equilibrium constant for the given reaction is 56.61
4. NaOH
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Answer:
SO the awnser is 76.9 trust me
Explanation: