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Alchen [17]
3 years ago
9

Please help thaank youu

Chemistry
1 answer:
krek1111 [17]3 years ago
6 0
First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
Co=58.933
Cl=35.45
H=1.008
O=15.999

Now, let's find the mass of each compound.

CoCl_2=58.933+2(35.45)=129.833
H_2O=2(1.008)+15.999=18.015

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

6(18.015)=108.09
129.833+108.09=237.923

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

\dfrac{108.09}{237.923}

\approx0.45431

Turn that into a percentage and you get 45.431%.
Hope this helps! :)
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