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ArbitrLikvidat [17]
3 years ago
11

Determine the magnitude of the force F1F1 component acting along the uu axis. Express your answer to three significant figures a

nd include the appropriate units. View Available Hint(s) Hint 1. How to approach the problemopened hint Since the uu and vv axes are not perpendicular, the force component magnitudes cannot be determined just using one proper trigonometric function. So we need to establish a triangle, a part of a parallelogram corresponding to the parallelogram law. Force F1F1 and its components will be the sides of that triangle. Then, finding the angles of the triangle and using the sine law should help to determine the force component magnitudes.
Physics
1 answer:
dybincka [34]3 years ago
5 0

The first image below shows force F1 and the axes.

Answer: (F_{1})_{u}= 3.62 kN

Explanation: The second figure below express the parallelogram method to calculate the u component of force F1.

The <u>Parallelogram</u> <u>Method</u> is a method to determine resultant force and is applied as described in the question above.

With the three components, F_{1},(F_{1})_{u} and (F_{1})_{v} and angles, it can be used the <u>Law</u> <u>of</u> <u>Sines</u>, which states:

\frac{a}{sin\alpha} =\frac{b}{sin\beta} =\frac{c}{sin\theta}

i.e., there is a relation of proportionality between an angle and its opposite side.

For the triangle below:

\frac{u}{sin30} =\frac{F_{1}}{sin105}

u=F_{1}\frac{sin(30)}{sin(105)}

u=7\frac{0.5}{0.966}

u = 3.62

The magnitude of the component acting along the u-axis is 3.62kN.

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If a 1000-pound capsule weighs only 165 pounds on the moon, how much work is done in propelling this capsule out of the moon's g
Bas_tet [7]

Answer:

  W = 1,307 10⁶ J

Explanation:

Work is the product of force by distance, in this case it is the force of gravitational attraction between the moon (M) and the capsule (m₁)

              F = G m₁ M / r²

              W = ∫ F. dr

              W = G m₁ M ∫ dr / r²

we integrate

             W = G m₁ M (-1 / r)

                 

We evaluate between the limits, lower r = R_ Moon and r = ∞

           W = -G m₁ M (1 /∞ - 1 / R_moon)

            W = G m1 M / r_moon

Body weight is

             W = mg

             m = W / g

The mass is constant, so we can find it with the initial data

For the capsule

            m = 1000/32 = 165 / g_moon

            g_moom = 165 32/1000

            .g_moon = 5.28 ft / s²

I think it is easier to follow the exercise in SI system  

           W_capsule = 1000 pound (1 kg / 2.20 pounds)

           W_capsule = 454 N

           W = m_capsule g

           m_capsule = W / g

           m = 454 /9.8

           m_capsule = 46,327 kg

Let's calculate

          W = 6.67 10⁻¹¹ 46,327   7.36 10²² / 1.74 10⁶

          W = 1,307 10⁶ J

7 0
3 years ago
A traffic light of weight 100 N is supported by two ropes that make 30-degree angle with the horizontal. What is the vertical co
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given,

traffic light weight = 100 N

angle at which the rope is supported = 30°

vertical component of force = ?

2 T sin \theta= W

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T = \dfrac{100}{2 sin 30^0}

T = 100\ N

T_{vertical} = T sin 30^0

T_{vertical} = 100\times \dfrac{1}{2}

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5 0
4 years ago
Pros and cons of nuclear energy
Deffense [45]

Answer: Pros and cons okay

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Pros: Produces no polluting gases. Waste is radioactive and safe disposal is very difficult and expensive.

Does not contribute to global warming.

Cons: Waste is radioactive and safe disposal is very difficult and expensive.

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