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katen-ka-za [31]
3 years ago
14

According to the kinetic-molecular theory, the average kinetic energy of gas particles depends on which factor?

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

Temperature.

Explanation:

Kinetic molecular theory of gases states that gas particles exhibit a perfectly elastic collision and are constantly in motion.

According to the kinetic-molecular theory, the average kinetic energy of gas particles depends on temperature.

This ultimately implies that, the average kinetic energy of gas particles is directly proportional to the absolute temperature of an ideal gas. Thus, an increase in the average kinetic energy of gas particles would cause an increase in the absolute temperature of an ideal gas.

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object. It is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).

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Is melting sugar a chemical or physical change? Please provide an explanation
liraira [26]

Answer:

Hola Amigo! Here's Ur Answer :D

Explanation:

The chemical reaction we are most familiar with is that of melting: sugar decomposes at a temperature ranging between 184 and 186°C. This is a very recent discovery we owe to a team of researchers in Illinois. Basically, when we heat sucrose gently, this produces a phenomenon known as “ apparent melting ”.

Happy to Help! :D

3 0
3 years ago
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What the answer question
Serga [27]

Answer:

it's a trigonal bipyramidial

Explanation:

because NH3 have 3 hydrogen atoms

4 0
3 years ago
If the distance between two objects is decreased to - of the original
Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

F = G\frac{m_1m_2}{R^2}The problem states  that  the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R

And the force at this distance would be written in terms of the same equation:

F_2 = G\frac{m_1m_2}{R_2^2}

Find the ratio between the final and the initial force:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}

Substitute the value for the final distance in terms of the initial distance:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}

Simplify:

\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}

This means the new force will be \frac{1}{100} of the original force.

8 0
3 years ago
Which of the following are correct for zero-order reactions?
GREYUIT [131]

Answer:

The answer is "Choice A and Choice B"

Explanation:

The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.

Let the Rate = k

As \frac{dx}{dt} \ rate\ \  K_0 doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.

By the rate k_0 =\frac{dx}{dt}, the created based and the reaction rate is about the same.

5 0
3 years ago
قدري بلا لون الجزء الثالث الحلقه ٩
nevsk [136]

Answer: <u>Arabic</u>

My destiny without color, the third part 9 episode

3 0
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