Answer:
Argon {Ar}
Explanation:
The noble gas used for a condensed electron configuration is the one before the element which you are configuring.
In this case, the element (Mn) is manganese
The noble gas that is before this element is Argon which is the row above it
so your configuration would be {Ar} 3d^5 4s^2
Answer:
a b
Explanation:
I think so take it with a grain of salt
It’s 65% average that your answer
<em>m Na₂CO₃: 23g×2 + 12g + 16g×3 = 106 g/mol</em>
------------------------------
1 mol ------- 106g
X ------------ 10,6g
X = 10,6/106
<u>X = 0,1 mol Na₂CO₃</u>
Answer:
See attached picture.
Explanation:
Hello,
In this case, for the given name, you can verify the structure on the attached picture, wherein you can see verify the presence of both the ethyl and methyl radicals at the third carbon as well as the triple bond at the first carbon.
Best regards.
