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7nadin3 [17]
3 years ago
13

Why are electromagnets more useful than permanent magnets in many

Physics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer: Electromagnets can be turned on and off by controlling the current

Explanation:

Tasya [4]3 years ago
5 0

B. By controlling the current, electromagnets can be turned on and off

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A way to charge insulators and conductors (the answer in 7 alphabets)
Fudgin [204]

Answer

RUBBING

Explanation:

3 0
3 years ago
When metals and nonmetals combined, first there is a complete transfer of charge to form cations and anions to complete their va
Llana [10]
<span> Then IONIC bonds are formed by electrostatic attraction.</span>
3 0
3 years ago
A mass of 0.34 kg is fixed to the end of a 1.4 m long string that is fixed at the other end. Initially at rest, he mass is made
frozen [14]

At time t seconds, the mass has angular speed

\omega = \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

and hence linear speed

v = (1.4\,\mathrm m) \omega = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

After 8 s, its linear speed is

v = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) (8\,\mathrm s) = 37.072 \dfrac{\rm m}{\rm s} \approx 37 \dfrac{\rm m}{\rm s}

and has centripetal acceleration with magnitude

a = \dfrac{v^2}{1.4\,\rm m} \approx 981.667\dfrac{\rm m}{\mathrm s^2} \approx 980 \dfrac{\rm m}{\mathrm s^2}

To maintain this linear speed, by Newton's second law the required centripetal force should have magnitude

F = (0.34\,\mathrm{kg}) a \approx 333.767\,\mathrm N \approx \boxed{330 \,\mathrm N}

5 0
2 years ago
A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre
ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined  using equation of motion

S=ut+\frac{1}{2}  at^2

where u is the initial velocity which is zero here

t is time taken, a is acceleration due to gravity

the position of  first drop after time t is given by

S_{1}  =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)

the position of  next drop at same time is

S_{2}  =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)

distance between them is S_{1} -S_{2}  is a(t-1)

from the above the difference will increase with the time

3 0
3 years ago
What is the acceleration of a racing car if it's speed is increased uniformly from 44 m /s to 66 m / s over an 11 second period
jolli1 [7]

Answer:

the acceleration of the race car is 2 m/s²

Explanation:

Given;

initial velocity of the race car, u = 44 m/s

final velocity of the race car, v = 66 m/s

time of motion of the race car, t = 11 s

The acceleration of the race car is  calculated as;

a = \frac{v-u}{t} \\\\a = \frac{66-44}{11} \\\\a = 2 \ m/s^2

Therefore, the acceleration of the race car is 2 m/s²

7 0
3 years ago
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