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kakasveta [241]
3 years ago
13

A compound was isolated and found to contain 72.2% magnesium and the rest nitrogen. What is the empirical formula of this compou

nd?
Chemistry
1 answer:
strojnjashka [21]3 years ago
6 0
Since the compound is 72.2% Mg then there would be 27.8% N. Then you can just change it to 72.2 g Mg and 27.8 g N.
then convert to moles by dividing by molecular mass.
72.2÷24.31=2.96 moles Mg
27.8÷14.01=1.98 moles N
then divided by the lowest number.
2.96÷1.98=1.5
Since it is 1.5 you multiply by 2. so you have 3 Mg
1.98÷1.98=1 N
so the empirical formula is Mg3N
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In this case, considering the described reaction which is also given as:

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2. Effect of removing H2

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Remoing H2 simply means we have more products and less reactant. Therefore, the product will be convert to reactant. Hence, the equilibrium position will shift to the left.

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