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geniusboy [140]
3 years ago
7

There are several types of inclined planes. A _______ is made by placing two inclined planes back to back. A ______ is made by w

rapping an inclined plane around a cylinder.
A.
wedge, lever
B.
lever, screw
C.
wedge, screw
D.
screw, wedge
Physics
2 answers:
Colt1911 [192]3 years ago
6 0
No the answer was c. it is a (wedge,screw)
liubo4ka [24]3 years ago
5 0

Answer: Wedge and screw.

Explanation :

There are several types of inclined planes.

A wedge is made by placing two inclined planes back to back. It is used in many ways like to cut, to split apart etc.

The examples of the wedge are a knife, axe, door stopper, scissors etc.

A screw is made by wrapping an inclined plane around a cylinder.

Hence, the correct option is (C) " wedge and screw".

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Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge
NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is V=\frac{1}{4\pi\epsilon} \frac{q}{d}

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

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If a marble is released from a height of 10 meters how long would it take to hit the ground?
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S = ut + 0.5at^2 

<span>10 = 0 + 0.5(9.81)t^2 {and if g = 10 then t^2 = 2 so t ~1.414}  </span>

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