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Alexandra [31]
3 years ago
10

Which of the following is a biotic factor in the picture above?

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
7 0

Answer:GRASS

Explanation:ITS THE ONLY THING LIVING

Sindrei [870]3 years ago
4 0

Answer:

Grass

Explanation:

Because its the only thing living

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Which equations represent precipitation reactions?
pychu [463]

A. : In this reaction one of the product, FeS is insoluble. Therefore, this is a precipitation reaction.


B. : In this reaction, the product is a solid(insoluble). So, this is a precipitation reaction too.


C.: In this reaction, both the products are soluble. So this is not a precipitation reaction.


D.: In this reaction, both the products are soluble. So this is not a precipitation reaction.


E. : In this reaction, the product AgCl is a precipitate. So, it is a precipitation reaction.

6 0
3 years ago
Read 2 more answers
Question 1 of 15<br> 2 Points<br> What is another name for a pure substance?<br> Answer here
maksim [4K]

Answer:

element

Explanation:

elements consist of pure substances

4 0
3 years ago
8 points
butalik [34]

Answer:

1.3 meters

Explanation: use newton third law equation.

5 0
3 years ago
How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water
erik [133]

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

 we need to convert g - mg

   500g = 500 x  10⁻³mg  = 0.5mg

   Concentration in parts per million = \frac{mass in mg}{Volume in liters}

Concentration in parts per million = \frac{0.5}{500000} = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

7 0
3 years ago
At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.
Goryan [66]

Answer:

Kc = 2.34 mol*L

Explanation:

The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

A + B ⇄ C + D

Kc = [C] * [D] / [A] * [B]

According to the reaction

Kc = [SO2]^2 * [O2]^2 / [SO3]^2

Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

0.450 --> 0 + 0 (Beginning of the reaction)

0.260 --> 0.260 + 0.130 (During the reaction)

0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)

Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

Kc = 2.34 mol*L

3 0
3 years ago
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